2017-04-07 58 views
-2

爲什麼我的後續子例程拋出每個派生表都必須有自己的別名錯誤?每個派生表都必須有它自己的別名Error?

sub ok_wait 
{ 
my $str= shift; 
$DBH = &connect or die "Cannot connect to the sql server \n"; 
$DBH->do("USE $str;"); 
my $stmt="select name,jobs_ok,jobs_wait from (select name,jobs_ok,jobs_wait from files order by name limit 5) t union all select 'others',sum(jobs_wait)as jobs_wait,sum(jobs_ok)as jobs_ok from(select jobs_wait,jobs_ok from files order by name limit -1 offset 5) t;"; 
my $sth = $DBH->prepare($stmt); 
$sth->execute() or die $sth->errstr; 
my $tmp = 0; 
while(my @row_array=$sth->fetchrow_array) 
{ 
if ($tmp == 0) { 
$var_ok .= "\[\"$row_array[0] \($row_array[2]\)\",$row_array[2]\]"; 
$var_wait .= "\[\"$row_array[0] \($row_array[1]\)\",$row_array[1]\]"; 
$tmp++; 
} 
$sth->finish; 
$DBH->disconnect(); 
} 
+0

也許是因爲你有派生表沒有別名? – billynoah

+0

上述更改顯示語法錯誤@ billynoah – SRVVANI

+0

您的SQL語法中有錯誤;檢查與您的MySQL服務器版本相對應的手冊,選擇正確的語法以在'from(選擇jobs_wait,jobs_ok中的文件order by name limit -1')附近使用@billynoah – SRVVANI

回答

0

改變了限值

"select name,jobs_ok,jobs_wait from ((select name,jobs_ok,jobs_wait from files order by name limit 5) union all (select 'others',sum(jobs_wait)as jobs_wait,sum(jobs_ok) as jobs_ok from (select jobs_wait,jobs_ok from files order by name limit 0 offset 5) foo)) foo "; 

注:未測試我剛纔輸入在這裏直接,但基本上你需要把一個別名到您的子查詢。

+0

顯示語法錯誤。 – SRVVANI

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對不起,我將保留GurV,但語法錯誤可能缺少括號 – Learning

+0

您的SQL語法錯誤;請查看與您的MySQL服務器版本相對應的手冊,以找到正確的語法以便在'from(從文件中選擇jobs_wait,jobs_ok姓名限制-1'@學習 – SRVVANI

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