需要幫助執行Oracle插入程序與PHP

Question

我試圖執行PHP中的存儲過程插入數據到表中，並不斷收到以下錯誤信息。

oci_execute（）[function.oci-執行]：ORA-01843：不是有效的月份 ORA-06512：在line 1

我本身跑我插入查詢，並沒有收到這個錯誤。這是程序代碼。

CREATE OR REPLACE PACKAGE trans_data AS 
    PROCEDURE INSERT_TRANSACTION_INFO(
    var_FName IN TRANSACTION.FIRST_NAME%type, 
    var_LName IN TRANSACTION.LAST_NAME%type, 
    var_DOB IN TRANSACTION.DOB%type, 
    var_InvoiceDate IN TRANSACTION.INVOICE_DATE%type, 
    var_ServiceCode IN TRANSACTION.SERVICE_CODE%type, 
    var_BilledAmt IN TRANSACTION.BILLED_AMT%type, 
    var_SSN IN TRANSACTION.SSN%type, 
    var_ServiceDate IN TRANSACTION.SERVICE_DATE%type, 
    var_VendorCode IN TRANSACTION.VENDOR_CODE%type, 
    var_TransStatus IN TRANSACTION.TRANS_STATUS%type, 
    var_Comp IN TRANSACTION.COMPANY%type, 
    var_State IN TRANSACTION.STATE%type, 
    var_Return OUT VARCHAR2 
); 
END trans_data; 

CREATE OR REPLACE PACKAGE BODY trans_data AS 
    PROCEDURE INSERT_TRANSACTION_INFO(
    var_FName IN TRANSACTION.FIRST_NAME%type, 
    var_LName IN TRANSACTION.LAST_NAME%type, 
    var_DOB IN TRANSACTION.DOB%type, 
    var_InvoiceDate IN TRANSACTION.INVOICE_DATE%type, 
    var_ServiceCode IN TRANSACTION.SERVICE_CODE%type, 
    var_BilledAmt IN TRANSACTION.BILLED_AMT%type, 
    var_SSN IN TRANSACTION.SSN%type, 
    var_ServiceDate IN TRANSACTION.SERVICE_DATE%type, 
    var_VendorCode IN TRANSACTION.VENDOR_CODE%type, 
    var_TransStatus IN TRANSACTION.TRANS_STATUS%type, 
    var_Comp IN TRANSACTION.COMPANY%type, 
    var_State IN TRANSACTION.STATE%type, 
    var_Return OUT VARCHAR2) 
    IS 
    BEGIN 
    INSERT INTO TRANSACTION 
     (FIRST_NAME, LAST_NAME, DOB, INVOICE_DATE, SERVICE_CODE, BILLED_AMT, 
     SSN, SERVICE_DATE, VENDOR_CODE, TRANSACTION_ID, TRANS_STATUS, COMPANY, 
     STATE) 
    VALUES 
     (var_FName, var_LName, to_date(var_DOB, 'MM/DD/YY'), 
     to_date(var_InvoiceDate, 'MM/DD/YY'), var_ServiceCode, var_BilledAmt, 
     var_SSN, to_date(var_ServiceDate, 'MM/DD/YY'), var_VendorCode, 
     SEQ_TRANSACTION_ID.nextval, var_TransStatus, var_Comp, var_State); 
    var_return := 'PASS'; 
    EXCEPTION 
    WHEN DUP_VAL_ON_INDEX THEN 
    var_return := 'DUPE'; 
    WHEN OTHERS THEN 
    var_return := 'FAIL'; 
    END INSERT_TRANSACTION_INFO; 
END trans_data; 

我的PHP代碼從前一頁接收到一個POST，我驗證所有字段都正確傳遞，並將它們綁定到變量。

//setup insert statement 
$stmts = OCI_Parse($c,"BEGIN ucs.trans_data.INSERT_TRANSACTION_INFO(
      :var_FName, :var_LName, :var_DOB, :var_InvoiceDate, :var_ServiceCode, :var_BilledAmt, :var_SSN, 
      :var_ServiceDate, :var_VendorCode, :var_TransStatus, :var_Comp, :var_State, :var_return); END;"); 

//bind input and output 
OCI_Bind_By_Name($stmts, ":var_FName", $FName); 
OCI_Bind_By_Name($stmts, ":var_LName", $LName); 
OCI_Bind_By_Name($stmts, ":var_DOB", $DOB); 
OCI_Bind_By_Name($stmts, ":var_InvoiceDate", $InvoiceDate); 
OCI_Bind_By_Name($stmts, ":var_ServiceCode", $ServiceCode); 
OCI_Bind_By_Name($stmts, ":var_BilledAmt", $BilledAmt); 
OCI_Bind_By_Name($stmts, ":var_SSN", $SSN); 
OCI_Bind_By_Name($stmts, ":var_ServiceDate", $ServiceDate); 
OCI_Bind_By_Name($stmts, ":var_VendorCode", $VendorCode); 
OCI_Bind_By_Name($stmts, ":var_TransStatus", $TransStatus); 
OCI_Bind_By_Name($stmts, ":var_Comp", $ComCode); 
OCI_Bind_By_Name($stmts, ":var_State", $State); 
OCI_Bind_By_Name($stmts, ":var_return", $Return, 4); 

//execute statement and add message to Return 
oci_execute($stmts); 
oci_commit($c); 

任何想法爲什麼使用01/01/11的日期會返回此消息嗎？讓我知道你是否需要我發佈任何其他信息。

Answer 1

您在過程中爲DATE參數聲明瞭錯誤的類型。

您的程序使用to_date解析日期，因此每個應該作爲VARCHAR傳遞。但是你宣佈你的論點爲DATE類型：

var_DOB IN TRANSACTION.DOB%type, 
var_InvoiceDate IN TRANSACTION.INVOICE_DATE%type, 
var_ServiceDate IN TRANSACTION.SERVICE_DATE%type, 

嘗試將其更改爲：

var_DOB IN VARCHAR2, 
var_InvoiceDate IN VARCHAR2, 
var_ServiceDate IN VARCHAR2, 

，看看它的工作原理呢。