Android，在tomcat服務器上傳文件

Question

我正在尋找能夠快速上傳來自我的android應用程序的圖像在tomcat服務器上的代碼。

目前，我還沒有發現Java代碼在Tomcat服務器放置（servlet的）

Answer 1

這裏是演示代碼。

import javax.servlet.*; 
import javax.servlet.http.*; 
import java.io.*; 
import org.apache.commons.fileupload.*; 
import org.apache.commons.fileupload.util.*; 
import org.apache.commons.fileupload.servlet.ServletFileUpload; 
public class UploadServlet extends HttpServlet{ 
    protected void doPost(HttpServletRequest request, HttpServletResponse response) 
    throws ServletException, IOException { 
    PrintWriter out = response.getWriter(); 
    out.print("Request content length is " + request.getContentLength() + "<br/>"); 
    out.print("Request content type is " + request.getHeader("Content-Type") + "<br/>"); 
    boolean isMultipart = ServletFileUpload.isMultipartContent(request); 
    if(isMultipart){ 
       ServletFileUpload upload = new ServletFileUpload(); 
     try{ 
       FileItemIterator iter = upload.getItemIterator(request); 
       FileItemStream item = null; 
       String name = ""; 
       InputStream stream = null; 
       while (iter.hasNext()){ 
            item = iter.next(); 
            name = item.getFieldName(); 
            stream = item.openStream(); 
       if(item.isFormField()){out.write("Form field " + name + ": " 
              + Streams.asString(stream) + "<br/>");} 
       else { 
         name = item.getName(); 
         if(name != null && !"".equals(name)){ 
         String fileName = new File(item.getName()).getName(); 
         out.write("Client file: " + item.getName() + " <br/>with file name " 
                + fileName + " was uploaded.<br/>"); 
         File file = new File(getServletContext().getRealPath("/" + fileName)); 
         FileOutputStream fos = new FileOutputStream(file); 
         long fileSize = Streams.copy(stream, fos, true); 
         out.write("Size was " + fileSize + " bytes <br/>"); 
         out.write("File Path is " + file.getPath() + "<br/>"); 
         } 
        } 
       } 
      } catch(FileUploadException fue) {out.write("fue!!!!!!!!!");} 
    } 
    } 
} 

Answer 2

使用
http://commons.apache.org/fileupload/
或者如果你使用的是Tomcat 7再使用的Servlet 3.0 API