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我創建了一個由服務構建的BroadcastReceiver。 BroadcastReceiver需要與服務進行交互,因此我將this
傳遞給構造函數。添加[廣播接收器] -Attribute並試圖編譯(與MonoDevelop的)後,我得到爲什麼BroadcastReceiver需要一個默認構造函數?
D:\Programme\MSBuild\Novell\Novell.MonoDroid.Common.targets(3,3): Error MSB4018: Unerwarteter Fehler bei der GenerateJavaStubs-Aufgabe.
System.InvalidOperationException: The type 'keepass2android.TimeoutService/MyBroadcastReceiver' needs to have a public default constructor.
at Xamarin.Android.Tasks.ManifestDocument.Merge(List`1 subclasses, List`1 selectedWhitelistAssemblies, Boolean embed)
at Xamarin.Android.Tasks.GenerateJavaStubs.Execute()
at Microsoft.Build.BackEnd.TaskExecutionHost.Microsoft.Build.BackEnd.ITaskExecutionHost.Execute()
at Microsoft.Build.BackEnd.TaskBuilder.ExecuteInstantiatedTask(ITaskExecutionHost taskExecutionHost, TaskLoggingContext taskLoggingContext, TaskHost taskHost, ItemBucket bucket, TaskExecutionMode howToExecuteTask, Boolean& taskResult) (MSB4018) (keepass2android)
爲什麼單爲Android需要這個默認的構造函數?它是否會用默認的構造函數創建我的BroadcastReceiver(在這種情況下,BroadcastReceiver將不能正常工作)?
中添加
receiver
標記如何以編程方式執行「exported = true」?我需要它,因爲我想爲我的BroadcastReceiver提供構造函數參數。 – JohnyTex