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我添加數據,並使用AJAX 上傳文件在PHP,但返回的PHP插入數據表需要應用程序的名字,我會寫在GetPhp.php應用程序的名字查詢需要用ajax
if(!appid)
{
var appname=document.getElementById("appname").value;
parameters ="appname="+appname;
/*var apptype=document.getElementById("apptype").value;
parameters ="apptype="+apptype;
var appurl=document.getElementById("appurl").value;
parameters ="appurl="+appurl;
var appguid=document.getElementById("appguid").value;
parameters ="appguid="+appguid;
var cname=document.getElementById("cname").value;
parameters ="cname="+cname;*/
$.ajaxFileUpload
(
{
url:'uploadplist.php',
secureuri:false,
fileElementId:'plist',
dataType: 'json',
data:{name:'logan', id:'id'},
success: function (data, status)
{
var plist=data.msg;
parameters +="&plist="+plist;
$.ajaxFileUpload
(
{
url:'uploadipa.php',
secureuri:false,
fileElementId:'ipa',
dataType: 'json',
data:{name:'logan1', id:'id1'},
success: function (data, status)
{
var ipa=data.msg;
parameters +="&ipa="+ipa;
$.ajaxFileUpload
(
{
url:'uploadprovision.php',
secureuri:false,
fileElementId:'provision',
dataType: 'json',
data:{name:'logan2', id:'id2'},
success: function (data, status)
{
var provision=data.msg;
parameters +="&provision="+provision;
$("input#appname").val('');
/*$("input#apptype").val('');
$("input#appurl").val('');
$("input#appguid").val('');
$("input#cname").val('');*/
$('#mask').hide();
$('.window').hide();
httprequest.onreadystatechange=alertContents;
httprequest.open('POST','GetPhp.php',true);
httprequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
httprequest.setRequestHeader("Content-length", parameters.length);
httprequest.setRequestHeader("Connection", "close");
httprequest.send(parameters);
},
error: function (data, status, e)
{
alert(e);
}
}
)
},
error: function (data, status, e)
{
alert(e);
}
}
)
},
error: function (data, status, e)
{
alert(e);
}
}
)
}
我只插入應用程序名稱其工作 當我刪除獲取appType,appurl,appquid的意見,CNAME其沒有上傳 鎊我
:謝謝你的建議 –
@Suresh不客氣 – Basic