使用多個左連接的MS Access SQL

Question

下面的連接在Access中工作，但我需要添加第四個連接。

FROM ((Agents 
LEFT JOIN Resignation_Pool ON Agents.PF = Resignation_Pool.PF) 
LEFT JOIN Teams    ON Agents.Team = Teams.ID) 
LEFT JOIN Skills    ON Agents.PF = Skills.PF 

當我添加第四個連接時，它不起作用。我知道Access對括號很奇怪，但我認爲我有他們屬於他們的地方。查詢只會永遠運行（它不應該長時間運行），我最終取消它。有什麼建議麼？

FROM (((Agents 
LEFT JOIN Resignation_Pool ON Agents.PF = Resignation_Pool.PF) 
LEFT JOIN Teams    ON Agents.Team = Teams.ID) 
LEFT JOIN Skills    ON Agents.PF = Skills.PF) 
LEFT JOIN OneMore    ON Agents.OM = OneMore.OM 

這是代碼的作品 - 我的實際查詢，而不是一個我發現看起來相似。

SELECT DISTINCT A02.PID, A02.PS, A02.PN, A02.PM, C01.RC, C01.IC, C01.RD 
INTO AutoCR 
FROM ((02_CorrectResults A02 
LEFT OUTER JOIN dbo_pol_PGI C01 
    ON (A02.PID = C01.PID and C01.PS = '999' and C01.PEDate >= #04/01/2012#)) 
LEFT OUTER JOIN dbo_pol_IL C02 
    ON C01.PID = C02.PID) 
LEFT OUTER JOIN dbo_pol_UN C03 
    ON C02.ILID = C03.ILID 

我添加另一個連接，這是行不通的。我嘗試使用內部連接，而不是Access。

SELECT DISTINCT A02.PID 
, A02.PS 
, A02.PN 
, A02.PM 
, C01.RC 
, C01.IC 
, C01.RD 
, C04.CCode 
, C04.PCode 
, C04.CForm, 
INTO AutoCR 
FROM (((02_CorrectResults A02 
LEFT OUTER JOIN dbo_rol_PGI C01 
    ON (A02.PID = C01.PID and C01.PS = '999' and C01.PEDate >= #04/01/2012#)) 
LEFT OUTER JOIN dbo_rol_IL C02 
    ON C01.PID = C02.PID) 
LEFT OUTER JOIN dbo_rol_UN C03 
    ON C02.ILID = C03.ILID) 
LEFT OUTER JOIN dbo_rol_HO C04 
    ON C03.UnID = C04.UnID 

Answer 1

您的查詢中有一個追蹤,。去掉它。

SELECT DISTINCT A02.PID 
, A02.PS 
, A02.PN 
, A02.PM 
, C01.RC 
, C01.IC 
, C01.RD 
, C04.CCode 
, C04.PCode 
, C04.CForm, <--- this was the problem 
INTO AutoCR 
FROM (((02_CorrectResults A02 
LEFT OUTER JOIN dbo_rol_PGI C01 
    ON (A02.PID = C01.PID and C01.PS = '999' and C01.PEDate >= #04/01/2012#)) 
LEFT OUTER JOIN dbo_rol_IL C02 
    ON C01.PID = C02.PID) 
LEFT OUTER JOIN dbo_rol_UN C03 
    ON C02.ILID = C03.ILID) 
LEFT OUTER JOIN dbo_rol_HO C04 
    ON C03.UnID = C04.UnID