Python 3岩石，紙張，剪刀問題

Question

我正在編寫一個編程作業，並且遇到了一個小小的障礙，我正在爲一個岩石，紙張，剪刀遊戲工作。該程序假設由用戶選擇4個選項中的1個，1）搖滾，2）紙，3）剪刀和4）退出。一旦玩家選擇了一個選項，計算機的選擇就會顯示出來，獲勝者將被宣佈，程序會詢問你是否想玩另一個遊戲。如果選擇y，則返回主菜單選擇另一個選項，其他任何選項都會顯示贏得的比賽數量，丟失的比賽以及比賽結束時的比賽數量。如果玩家選擇4，則該程序應該說「退出程序...」，並且應該顯示遊戲結果。

這裏是我的問題：

1. 一旦你做出了第一個選擇，顯示贏家和程序返回到主菜單。如果您再次選擇，它會通知您電腦選擇的內容，然後詢問您是否想再次播放。 Y會帶你回到主菜單，電腦的選擇永遠不會改變，無論你選擇什麼遊戲，總是會以與第一場比賽相同的結果結束。如果您選擇不再玩，那麼會出現贏，輸和遊戲的數量（這似乎是正常運行）。

2. 退出選項會將您帶回主菜單，而不是顯示遊戲結果。我不知道該在哪裏發表聲明。

任何有關這些問題的幫助，將不勝感激。

謝謝

#import module 
import random 

def main(): 
    #create a variable to control the loop 
    play_again = 'y' 

    #create a counter for tied games, computer games and player games 
    tied_games = 0 
    computer_games = 0 
    player_games = 0 

    #display opening message 
    print("Let's play rock, paper scissors!") 

    computer_choice = process_computer_choice() 

    player_choice = process_player_choice() 

    winner = determine_winner(player_choice, computer_choice) 

    #setup while loop for playing multiple games 
    while play_again == 'y' or play_again == 'Y': 

     process_computer_choice() 

     process_player_choice() 

     #use a if else statement to print the computers choice 
     if computer_choice == 1: 
      print('computer chooses rock.') 

     elif computer_choice == 2: 
      print('computer chooses paper.') 

     else: 
      print('computer chooses scissors.') 

      #call the determine winner function  
      determine_winner(player_choice, computer_choice) 

     #check who won the game and add 1 to the correct counter 
     if winner == 'computer': 
      computer_games += 1 

     elif winner == 'player': 
      player_games += 1 

     else: 
      tied_games += 1 

     #ask the user if they would like to play again  
     play_again = input('would you like to play again? (enter y for yes): ') 

    #display number of games that were won by the computer, the player and that were tied 
    print() 
    print('there was', tied_games, 'tied games.') 
    print('the player won', player_games, 'games.') 
    print('The computer won', computer_games,'games.') 

#define the process computer function 
def process_computer_choice(): 

    #setup computer to select random integer between 1 and 3 
    choice1 = random.randint(1, 3) 

    #return the computers choice 
    return choice1 

#define the process player function 
def process_player_choice(): 

    #add input for players choice 
    print() 
    print('  MENU') 
    print('1) Rock!') 
    print('2) Paper!') 
    print('3) Scissors!') 
    print('4) Quit') 
    print() 

    player_choice = int(input('Please make a selection: ')) 

    #add if statement for quit option 
    if player_choice == 4: 
     print('Exiting program....') 

    #validate if the user enters a correct selection 
    while player_choice != 1 and player_choice != 2 and player_choice != 3 and player_choice != 4: 

     #print a error message if the wrong selection is entered 
     print('Error! Please enter a correct selection.') 

     player_choice = int(input('Please make a selection: ')) 

    #return the players choice 
    return player_choice 

#define the determine winner function 
def determine_winner(player_choice, computer_choice): 

    #setup if else statements for each of the 3 computer selections 
    if computer_choice == 1: 
     if player_choice == 2: 
      print('Paper wraps rock. You win!') 
      winner = 'player' 

     elif player_choice == 3: 
      print('Rock smashes scissors. The computer wins!') 
      winner = 'computer' 

     else: 
      print('The game is tied. Try again.') 
      winner = 'tied' 

    if computer_choice == 2: 
     if player_choice == 1: 
      print('Paper wraps rock. The computer wins!') 
      winner = 'computer' 

     elif player_choice == 3: 
      print('Scissors cut paper. You win!') 
      winner = 'player' 

     else: 
      print('The game is tied. Try again.') 
      winner = 'tied' 

    if computer_choice == 3: 
     if player_choice == 1: 
      print('Rock smashes scissors. You win!') 
      winner = 'player' 

     elif player_choice == 2: 
      print('Scissors cut paper. The computer wins!') 
      winner = 'computer' 

     else: 
      print('The game is tied. Try again.') 
      winner = 'tied' 

    return winner 

main() 

Answer 1

對於問題1，這是因爲您在循環之前設置的計算機和球員的選擇，從不更新它們。你的循環的開始更改爲：

while play_again == 'y' or play_again == 'Y': 
    computer_choice = process_computer_choice() 
    player_choice = process_player_choice() 

另外，還可以檢查輸入的贏家，因爲它是第一輪技術上冗餘環路之前刪除的代碼行。

對於問題2，只需添加結果選擇了4後，像這樣：

if player_choice == 4: 
     print('Exiting program....') 
     print('there was', tied_games, 'tied games.') 
     print('the player won', player_games, 'games.') 
     print('The computer won', computer_games,'games.') 
     sys.exit() # be sure you add 'import sys' to the beginning of your file 

此外，線路在主迴路determine_winner(player_choice, computer_choice)縮進所以它纔會被調用，如果計算機選擇剪刀，所以你應該unindent：:)

Answer 2

您還沒有分配給computer_choice或player_choice一遍，但使用它的價值。

while play_again == 'y' or play_again == 'Y': 

    process_computer_choice() 

    process_player_choice() 

應該

while play_again == 'y' or play_again == 'Y': 

    computer_choice = process_computer_choice() 

    player_choice = process_player_choice() 

至於退出只是在退出選擇突破。您必須儘早從process_player_choice返回，並在main中執行一些操作。

所以在process_player_choice：

if player_choice == 4: 
    print('Exiting program....') 
    return 

，並在主： player_choice = process_player_choice（）

if player_choice == 4: 
    return 

winner = determine_winner(player_choice, computer_choice) 

#setup while loop for playing multiple games 
while play_again == 'y' or play_again == 'Y': 

    computer_choice = process_computer_choice() 

    player_choice = process_player_choice() 
    if player_choice == 4: 
     break