保存並獲取微調項目選擇

Question

我想保存微調值並檢索所選項目的值 問題是我有一個微調整數和兩個微調長 ，我不知道如何獲得值長期受 我要讓這種方法能夠設置在同一方法整型和長和iwant保存這些VAL到SP，並獲得使用這種方法，

private void spinnerVal(int spinnerID, int move, int selection){ 
Spinner sp = (Spinner) findViewById(spinnerID); 
ArrayList<Integer> spinnerOption = new ArrayList<>(); 
for (int i = 0; i < 50; i+=move) { 
    spinnerOption.add(i); 
} 
ArrayAdapter<Integer> integerArrayAdapter = new ArrayAdapter<>(this, R.layout.spinner_item, spinnerOption); 
integerArrayAdapter.setDropDownViewResource(R.layout.support_simple_spinner_dropdown_item); 
sp.setAdapter(integerArrayAdapter); 
sp.setSelection(selection); 
sp.setOnItemSelectedListener(this); 

} 

這是我對項目選擇的方法

@Override 
public void onItemSelected(AdapterView<?> parent, View view, int position, long id) { 
    Editor editor; 
    switch (parent.getId()) { 
     case R.id.spinner1 /*2131492981*/: 
      myServer.counter1 = Integer.valueOf(parent.getItemAtPosition(position).toString()); 
      editor = PreferenceManager.getDefaultSharedPreferences(this).edit(); 
      editor.putInt("counter1", myServer.counter1); 
      editor.apply(); 
      return; 
     case R.id.spinner2 /*2131492983*/: 
      myServer.counter2 = (long) (Integer.valueOf(parent.getItemAtPosition(position).toString()) * 1000); 
      editor = PreferenceManager.getDefaultSharedPreferences(this).edit(); 
      editor.putLong("counter2", myServer.counter2); 
      editor.apply(); 
      return; 
     case R.id.spinner3 /*2131492985*/: 
      myServer.counter3 = (long) (Integer.valueOf(parent.getItemAtPosition(position).toString()) * 1000); 
      editor = PreferenceManager.getDefaultSharedPreferences(this).edit(); 
      editor.putLong("counter3", myServer.counter3); 
      editor.apply(); 
      return; 
     default: 
      return; 

    } 

} 

Answer 1

你一個當Spinner項目是Long時，使用Integer.valueOf()來解析Long值。您必須使用Long.parseLong()或Long.valueOf()代替解析Long項目。