MySQL查詢2個表中，1個JSON輸出

Question

DELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNTDELETE ACCOUNT

Answer 1

$query = " 
      SELECT  p.permission_type, 
         m.empid, 
         m.name 

       FROM  members as m 

     INNER JOIN  permissions as p 

       ON  p.is_deleted = m.is_deleted 
      "; 

。

$JSON_output[] = array('Permission Type'  => $row['permission_type'], 
         'Employee ID'   => $row['empid'], 
         'Full Name'    => $row['name'], 
        ); 
} 

Answer 2

0會導致一些問題，因爲這意味着空或null。您可以在is_deleted列是/否或y/n上查詢您是否想要節省一些空間。這不會引起衝突。

當數字值爲整數1+時，您可以使用數字值。

Answer 3

<?php 

    $query = " 
    SELECT p.`permission value`,p.permission, m.emp_id, m.username FROM Members as m 
    INNER JOIN Permission as p ON p.is_deleted = m.is_deleted 
    "; 

     $result = mysql_query($query); 
      if (!$result) { 
       $ErrorMessage = 'Invalid query: ' . mysql_error() . "\n"; 
       $ErrorMessage .= 'Whole query: ' . $query; 
      die($ErrorMessage); 
    } 

    $JSON_output = array(); 
    while ($row = mysql_fetch_assoc($result)){ 
     $JSON_output[] = $row; 
    } 

header("Content-Type: application/json"); 
$JSON_output = json_encode($JSON_output); 

echo $JSON_output . ""; 

mysql_close($Connection); 
?>