運行fql facebook查詢無法從網址發表評論時出錯？

Question

我有一個示例代碼：

require 'facebook.php'; 
$facebook = new Facebook(array(
    'appId' => xxx, 
    'secret' => xxx, 
    'cookie' => true, 
)); 

$my_url = 'http://didong.net/tru-than.html'; 
$fpl = " 
SELECT post_fbid, fromid, object_id, text, time FROM comment WHERE object_id IN 
    (SELECT comments_fbid FROM link_stat WHERE url ='".$my_url."') 
"; 
$params = array(
    'method' => 'fql.query', 
    'query' => $fpl, 
); 

//Run Query 
$result = $facebook->api($params); 
print_r($result); 

=>結果是：array()

但是，當我瀏覽器鏈接https://graph.facebook.com/comments/?ids=http://didong.net/tru-than.html =>結果有意見

=>如何運行FQL Facebook查詢到獲得對此鏈接的評論？

Answer 1

$fql = urlencode(
    "SELECT post_fbid, fromid, object_id, text, time FROM comment WHERE object_id IN (SELECT comments_fbid FROM link_stat WHERE url ='http://didong.net/tru-than.html')" 
); 

// Run fql query                      
$fql_query_url = 'https://graph.facebook.com/'. 
    '/fql?q='.$fql. 
    '&'.$access_token; 
$fql_query_result = file_get_contents($fql_query_url); 
$fql_query_obj = json_decode($fql_query_result, true); 

//display results of fql query                  
echo '<pre>'; 
print_r("query results:\n\n"); 
print_r($fql_query_obj); 
print_r('Rows: '.count($fql_query_obj['data'])); 
echo '</pre>'; 

現場演示：

http://plooza.com/fql/fql_comments.php