正則表達式評估「不」和「不」等於

Question

我需要能夠匹配一個句子的單詞序列，並試圖使用正則表達式，但由於某種原因，正則表達式評估「不」和「不」相等。代碼仍然處於模擬階段，但這個想法是一個系統拋出一個錯誤，我需要看看是否包含一個特定的語言。這裏是代碼。

 string message = "The field could not be calculated because the following field(s) have no value or have invalid values: [field1]."; 
     string[] sentences = message.Split(' '); 

     string pattern = "have no value or have invalid values:"; 
     string[] pattern1 = pattern.Split(' '); 

     string[] result = new string[pattern1.Length]; 
     int i = 0; 

     foreach (string p in pattern1) 
     { 
      foreach (string s in sentences) 
      { 
       System.Console.Write("{0,24}", s); 

       if (System.Text.RegularExpressions.Regex.IsMatch(s, p, System.Text.RegularExpressions.RegexOptions.IgnoreCase)) 
       { 
        System.Console.WriteLine(" (match for '{0}' found)", p); 
        result[i] = s.Trim(); 
        i++; 
        break; 
       } 
       else 
       { 
        System.Console.WriteLine(); 
       } 
      } 
     } 

     bool isEqual = pattern1.SequenceEqual(result); 
     if (isEqual) 
     { 
      System.Console.WriteLine("Match Found"); 
     } 
     else 
     { 
      System.Console.WriteLine("Match NOT Found"); 
     } 

Answer 1

你的代碼是在這種情況下，使用正則表達式是no（從pattern1，您可以通過拆分have no value or have invalid values:了）

好not肯定是對正則表達式模式no比賽 - 因爲not開始與no。

如果你想更具體的你可以介紹一下word boundary \b

//other code 

foreach (string p in pattern1) 
{ 
    foreach (string s in sentences) 
    {    
     //wrap your pattern in word boundaries 
     string pat = "\b" + p + "\b" 

     //use the new wrapped pattern 
     if (System.Text.RegularExpressions.Regex.IsMatch(s, pat, System.Text.RegularExpressions.RegexOptions.IgnoreCase)) 
     { 
      System.Console.WriteLine(" (match for '{0}' found)", pat); 
     } 
     else 
     { 
      //... 
     } 
    } 
}