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Question

我有數組一個問題，有沒有我的朋友:)

我有一個數組：

Array 
(
    [0] => 2012163115 
    [1] => 2012163115 
    [2] => 2012161817 
    [3] => 201214321971 
    [4] => 201214321971 
    [5] => 201214321971 
) 

，我需要這個與所有的變量出現不止一次

Array 
(
    [0] => 2012163115 
    [1] => 201214321971 
) 

我試試這個

foreach ($array as $val) { 
        if (!in_array($val, $array_temp)) { 
         $array_temp[] = $val; 
        } else { 
         array_push($duplis, $val); 
        } 
       } 

但結果是

Array 
(
    [0] => 2012163115 
    [1] => 201214321971 
    [2] => 201214321971 
) 

哪裏是我的錯？感謝幫助！

Answer 1

$array = array(
    '2012163115', 
    '2012163115', 
    '2012161817', 
    '201214321971', 
    '201214321971', 
    '201214321971', 
); 

$duplication = array_count_values($array); 
$duplicates = array(); 
array_walk($duplication, function($key, $value) use (&$duplicates){ 
    if ($key > 1) 
    $duplicates[] = $value; 
}); 
var_dump($duplicates); 

Answer 2

array_unique()是否適合您。

編輯：OPS我沒有注意到「不止一次」的條款，在這種情況下：

$yourArray = array('a', 'a', 'b', 'c'); 

$occurrences = array(); 

array_walk($yourArray, function($item) use(&$occurrences){ 

    $occurrences[$item]++; 

}); 


$filtered = array(); 

foreach($occurrences as $key => $value){ 

    $value > 1 && $filtered[] = $key; 

} 

var_dump($filtered); 

Answer 3

請參閱http://php.net/manual/en/function.array-unique.php#81513

這些被添加的字符以使SO接受這個職位！

Answer 4

$array_counting = array(); 
foreach ($array as $val) 
    if (! in_array($val, $array_counting)) 
    { 
     $array_counting[$val] ++; // counting 
    } 

$array_dups = array(); 
foreach ($array_counting as $key => $count) 
{ 
    if ($count > 1) 
     $array_dups[] = $key; // this is more than once 
}