SQL查詢到兩個字段篩選組合

Question

ArticleNumber Company Storage 
01-01227  12  2 
01-01227  2  1 'filtered by company/storage in combination 
01-01227  5  1 
01-01227  12  1 'filtered by company/storage in combination 
01-44444  5  4 'filtered by not match the articlenumber 

欲進行過濾，從而含有行（company = 12和storage = 1）和（company = 2和storage = 1）將被過濾掉的結果集，並過濾上articlenr。

這就是我想到的，但肯定有一個更簡單的方法來做出該查詢？

SELECT * FROM MyTable 
where 
    (Company=2 and Storage<>1 and ArticleNumber='01-01227') 
or 
    (Company=12 and Storage<>1 and ArticleNumber='01-01227') 
or 
    (Company<>2 and Company<>12 and ArticleNumber='01-01227') 

結果後我：

ArticleNumber Company Storage 
    01-01227  12  2 
    01-01227  5  1 

Answer 1

這將返回你要查找的內容：

select * from t 
where articleNumber = '01-01227' and (
    (company != 12 or storage != 1) and 
    (company != 2 or storage != 1) 
) 

結果：

ARTICLENUMBER COMPANY STORAGE 
01-01227  12  2 
01-01227  5  1 

沒有必要在此解決方案的加入，這使它相當快速和高性能。除此之外，您可以輕鬆地添加restrinctions成對。

Answer 2

一個可能的方法來簡化這一過程是建立一個稱爲表，說company_storage_exclude與Company和Storage列。然後，只需與要排除對Company和Storage填充這些值，然後你可以這樣做：

select * 
from MyTable 
where (Company,Storage) not in (select Company,Storage from company_storage_exclude) 
and ArticleNumber='01-01227'; 

或：

select a.* 
from MyTable a 
left join company_storage_exclude b 
on (a.Company=b.Company and a.Storage=b.Storage) 
where b.Company is null and b.Storage is null 
and ArticleNumber='01-01227'; 

Answer 3

SELECT * FROM MyTable 
WHERE 
    NOT (Company=12 and Storage=1) 
AND 
    NOT (Company=5 and Storage=1) 
AND 
    ArticleNumber='01-01227' 

甚至更​​好

SELECT * FROM MyTable 
WHERE 
    NOT ((Company=12 OR Company=5) AND Storage=1) 
AND 
    ArticleNumber='01-01227' 

Answer 4

沿着這些線？

SELECT * FROM MyTable 
where 
    ArticleNumber='01-01227' 
AND 
    (Company IN (2,12) AND Storage <> 1 
    OR 
    Company NOT IN (2,12) 
    ) 

Answer 5

SELECT * FROM MyTable 
WHERE ArticleNumber='01-01227' 
AND (Company NOT IN (2,12) OR Storage <> 1)