socket.io 2.0獲取連接的客戶端在一個房間裏

Question

你怎麼能使用socket.io 2.0

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我已經嘗試過類似的問題的解決檢索所有連接的客戶端在一個房間：https://stackoverflow.com/a/45160538/2189845

var sockets = io.in("room_name") 
Object.keys(sockets.sockets).forEach((item) => { 
console.log("TODO: Item:", sockets.sockets[item].id)    
}) 

但是，無論房間如何，這都會在所有套接字連接上循環。所以，上面的代碼給出了相同的結果：

Object.keys(io.sockets.sockets).forEach((item) => { 
    console.log("general socket: Item:", item); 
}); 

Answer 1

不幸的是，這個答案並不完全滿足有機磷農藥的問題。如果您正在使用socket.io-redis管理套接字連接，你可以得到連接的客戶端一樣

io.of('/').adapter.clients((err, clients) => { 
    console.log(clients); // an array containing all connected socket ids 
}); 

io.of('/').adapter.clients(['room1', 'room2'], (err, clients) => { 
    console.log(clients); // an array containing socket ids in 'room1' and/or 'room2' 
}); 

// you can also use 

io.in('room3').clients((err, clients) => { 
    console.log(clients); // an array containing socket ids in 'room3' 
}); 

這是來自：https://github.com/socketio/socket.io-redis#redisadapterclientsroomsarray-fnfunction

Answer 2

嘗試：

io.sockets.clients('room_name').forEach(function(item) { 
    console.log(item.id);//any property of socket you want to print 
}); 

或者你可以嘗試：

var clients = io.sockets.adapter.rooms['room_name'].sockets; 
for (var clientId in clients) { 

    //this is the socket of each client in the room. 
    var SocketofClient = io.sockets.connected[clientId]; 
    console.log(SocketofClient.id); 
}