獲得在angularjs

Question

我使用自定義過濾器對我的表中的內容無法讀取空自定義過濾器的特性「的indexOf」的搜索搜索我的自定義濾鏡功能是

return function(data, search) { 
    if(angular.isDefined(search)) { 
     var results = []; 
     var i; 

     var searchVal = $filter('lowercase')(search); 
     for(i = 0; i < data.length; i++){ 
     var name = $filter('lowercase')(data[i].name); 
     var description = $filter('lowercase')(data[i].description); 
     if(name.indexOf(searchVal) > -1 || description.indexOf(searchVal) > -1){ 
      results.push(data[i]); 
     } 
     } 
     return results; 
    } else { 
     return data; 
    } 
    }; 

當我把任何文本搜索框它會得到

TypeError: Cannot read property 'indexOf' of null 

Answer 1

if((name !=null && name.indexOf(searchVal) > -1) || (description!=null && description.indexOf(searchVal) > -1)){ 
      results.push(data[i]); 
    } 

名稱或說明是給空值試試上面的代碼

Answer 2

檢查爲空條件

return function(data, search) { 
if(angular.isDefined(search)) { 
    var results = []; 
    var i; 

    var searchVal = $filter('lowercase')(search); 
    for(i = 0; i < data.length; i++){ 
    var name = $filter('lowercase')(data[i].name); 
    var description = $filter('lowercase')(data[i].description); 
    if(name !== null && description !== null){ 
    if(name.indexOf(searchVal) > -1 || description.indexOf(searchVal) > -1){ 
     results.push(data[i]); 
    } 
    } 
    } 
    return results; 
} else { 
    return data; 
} 
};