超時是無法通過pika.Blocking連接發送

Question

我想寫一個客戶端程序從rabbitmq服務器接收，我想要設置超時。在指定的時間之後，客戶端應該停止使用隊列中的消息並退出。

我正在使用與阻止連接的鼠標。我看到在阻塞連接中定義的add_timeout（delay，callback），但是當我嘗試使用時，我收到以下錯誤，如下所示。

[*] Waiting for logs. To exit press CTRL+C 
Traceback (most recent call last): 
    File "/root/workspace/Misc/misc/pika_samples/log_recieve.py", line 39, in <module> 
    channel.start_consuming() 
    File "/usr/lib/python2.6/site-packages/pika/adapters/blocking_connection.py", line 293, in start_consuming 
    self.transport.connection.process_data_events() 
    File "/usr/lib/python2.6/site-packages/pika/adapters/blocking_connection.py", line 103, in process_data_events 
    self.process_timeouts() 
    File "/usr/lib/python2.6/site-packages/pika/adapters/blocking_connection.py", line 160, in process_timeouts 
    self._timeouts[timeout_id]['handler']() 
TypeError: callback() takes exactly 4 arguments (0 given) 

這是我的客戶端程序。我沒有運行任何服務器來模擬超時條件。

#!/usr/bin/env python 
import pika 
import sys 

connection = pika.BlockingConnection(pika.ConnectionParameters(host='localhost')) 
channel = connection.channel() 
channel.exchange_declare(exchange='topic_logs',type='topic') 
result = channel.queue_declare(exclusive=True) 
queue_name = result.method.queue 
binding_keys = "#" 
for binding_key in binding_keys: 
    channel.queue_bind(exchange='topic_logs',queue=queue_name, 
        routing_key=binding_key) 

print ' [*] Waiting for logs. To exit press CTRL+C' 
def callback(ch, method, properties, body): 
    print " [x] %r:%r" % (method.routing_key, body,) 
    channel.stop_consuming() 
connection.add_timeout(10, callback) 
channel.basic_consume(callback,queue=queue_name,no_ack=True) 
channel.start_consuming() 

---

如果我得到超時時間指定的客戶端內的消息應該打印的郵件，應停止進一步消耗。

任何人都可以幫助我如何在客戶端設置超時？

Answer 1

這個問題在截止日期。然後截止時刻發生沒有任何參數調用的函數回調。所以你可以改變你的代碼

def callback(ch=None, method=None, properties=None, body=None): 
    if ch is None or method is None or properties is None or body is None: 
     print "Deadline" 
    else: 
     print " [x] %r:%r" % (method.routing_key, body,)