控制器中的Codeigniter 2按鈕

Question

這是我的問題'if（！empty（$ _ POST ['btn_editinventory]））'正在工作，但如果我點擊btndeleteinventory它也會執行我的btneditinventory中的代碼。任何人都知道我怎麼會糾正我的狀態在我的控制器，如果你有這樣的看法兩個按鈕：

<input type="button" value="Edit" name="btn_editinventory" id="btn_editinventory" onclick="validate_editinventory();"/> 
    <input type="button" value="Delete" name="btn_deleteinventory" id="btn_deleteinventory" onclick="validate_deleteinventory();"/> 

預先感謝您的幫助！ :)

這是我的看法

<link rel="stylesheet" type="text/css" href="<?php echo base_url('assets/css/mystyle.css') ?>"> 

<div id="content"> 
<form action="edit_delete_others2" method="POST" id='frm_otherequips2' name="frm_otherequips2"> 
    <fieldset id="edit_other"> 
     <legend>Inventory Details</legend> 
     <table> 
      <tr> 
       <?php $otherequips = $other2->Equipment; 
         $otherdesc = $other2->ItemDescription; 
         $otherID = $other2->ID; 
         $otherserialnum = $other2->SerialNumber; 
       ?> 
       <td>Equipment</td> 
       <?php // if(isset($other)) { ?> 
       <td><input type="text" id="txt_editotherequip" name="txt_editotherequip" value="<?php echo $otherequips // echo (isset($other->Equipment) AND $other->Equipment) ? $other->Equipment:''; ?>"/></td> 

       <td>Item Description</td> 
       <td><input type="text" id="txt_editotherdesc" name="txt_editotherdesc" value="<?php echo $otherdesc // echo (isset($other->ItemDescription) AND $other->ItemDescription) ? $other->ItemDescription:''; ?>"/></td> 
       <td style="visibility: hidden;"><input type="text" id="txt_editotherID" name="txt_editotherID" value="<?php echo $otherID //echo (isset($other->ID) AND $other->ID) ? $other->ID:''; ?>"/></td> 
      </tr> 
      <tr> 
       <td>Serial Number</td> 
       <td><input type="text" id="txt_editotherserialnum" name="txt_editotherserialnum" value="<?php echo $otherserialnum // echo (isset($other->SerialNumber) AND $other->SerialNumber) ? $other->SerialNumber:''; ?>"/></td> 
       <?php // } ?> 
      </tr> 
      <tr> 
       <td><input type="button" id="btn_editother" name="btn_editother" value="Edit" onclick="validate_edit_otherequip();"/></td> 
       <td><input type="button" id="btn_deleteother" name="btn_deleteother" class="btn_deleteother" value="Delete" onclick="validate_delete_otherequip();"/></td> 
      </tr> 
     </table> 
    </fieldset> 
</form> 
</div> 

這裏是我的javascript：

<script> 
function validate_edit_otherequip(){ 
    if(document.getElementById('txt_editotherequip').value === ""){ 
     alert('Please Input Equipment!'); 
     return false; 
    } 
    else if(document.getElementById('txt_editotherdesc').value === ""){ 
     alert('Please Input Item Description'); 
     return false; 
    } 
    else if(document.getElementById('txt_editotherserialnum').value === ""){ 
     alert('Please Input Serial Number'); 
     return false; 
    } 
    else{ 
     var y; 
     if(confirm("Are you sure you want to save updated data?") === true){ 
      var y = document.forms['frm_otherequips2'].submit(); 
     } 
     else if(confirm("Are you sure you want to save updated data?") === false){ 
      return false; 
     } 
    } 
} 

function validate_delete_otherequip(){ 
    var x; 
    if(confirm("Are you sure you want to delete this data?") === true){ 
     var x = document.forms['frm_otherequips2'].submit(); 
    } 
    else if(confirm("Are you sure you want to delete this data?") === false){ 
     return false; 
    } 
} 

，這裏是我的控制器：

public function edit_delete_others2($id){ 
      $data_other['other2'] = $this->inventory_model->other_search($id); 
      $this->load->view('homeview'); 
      $this->load->view('frm_otherequips2', $data_other); 
      $this->load->view('footer_view'); 
} 

我不知道如何在按鈕中有條件。

Answer 1

至於你的兩個按鈕有一個name屬性，這是很容易在你的控制器來處理

public function edit_delete_others2($id){ 

    if($this->input->post('btn_editinventory')) { 

     // Do your edit stuff 

    } elseif($this->input->post('btn_deleteinventory')) { 

     // Do your delete stuff 
    } 
} 

按鈕永遠不會在郵寄時，你不點擊它，這是爲什麼它的工作原理