此解決方案適用於我。你需要調整它才能將它傳遞給模板。
from django.db.models import Count
all_countries = Country.objects.annotate(Count('story')).order_by('-story__count')
for country in all_countries:
print "Country %s (%s)" % (country.name, country.story__count)
all_cities = City.objects.filter(country = country).annotate(Count('story')).order_by('-story__count')
for city in all_cities:
print "\tCity %s (%s)" % (city.name, city.story__count)
更新
這裏是將這些信息發送到模板的一種方式。這一個涉及使用自定義過濾器。
@register.filter
def get_cities_and_counts(country):
all_cities = City.objects.filter(country = country).annotate(Count('story')).order_by('-story__count')
return all_cities
查看:
def story_counts(request, *args, **kwargs):
all_countries = Country.objects.annotate(Count('story')).order_by('-story__count')
context = dict(all_countries = all_countries)
return render_to_response(..., context)
而且在你的模板:
{% for country in all_countries %}
<h3>{{ country.name }} ({{ country.story__count }})</h3>
{% for city in country|get_cities_and_counts %}
<p>{{ city.name }} ({{ city.story__count }})</p>
{% endfor %}
{% endfor %}
更新2
變異與模型的自定義方法。
class Country(models.Model):
name = models.CharField(max_length=50)
def _get_cities_and_story_counts(self):
retrun City.objects.filter(country = self).annotate(Count('story')).order_by('-story__count')
city_story_counts = property(_get_cities_and_story_counts)
這可以讓您避免定義過濾器。模板代碼更改爲:
{% for country in all_countries %}
<h3>{{ country.name }} ({{ country.story__count }})</h3>
{% for city in country.city_story_counts %}
<p>{{ city.name }} ({{ city.story__count }})</p>
{% endfor %}
{% endfor %}
我意識到是這樣做的方法很多,但不知道是否有利用Django的ORM的方式,像這樣的答案在這裏,http://stackoverflow.com/questions/ 1010848 /遍歷多維字典在Django中/ 1011145#1011145 – Maverick 2010-08-25 09:33:50