我有一個填充數據庫數據的表單。 之前開始描述我的問題,有些片段:JSP下拉列表不提交對象
一類:
// @Entity for areas
public class Area {
@Id
@Column(name = "area")
private String area;
@Column(name = "deleted")
private boolean deleted;
getter/setter
}
二等
// @Entity for employees
public class Employee {
@Id
@GeneratedValue
@Column(name = "ID")
private long id;
@ManyToOne
@JoinColumn(name = "area")
private Area area;
@Column(name = "name")
private String name;
getter/setter
在EmployeeController的方法調用,數據返回到JSP
protected String createDialog(@PathVariable("id") Long id, Model model){
Employee employee = id == 0 ? new Employee() : employeeService.findById(id);
//return employee
model.addAttribute("employeeModel", employee);
//add data needed to create dropdown holding areas
//areaService.findAll returns a List<Area>
model.addAttribute("areas", areaService.findAll(
new Sort(
Sort.Direction.ASC,
"area"
)
));
return "employees/dialogUpdateEdit";
}
jsp,顯示區域的下拉列表,如果沒有n EW員工返回,已知數據
<form:form action="employees/ajax" commandName="employeeModel" method="POST" id="createForm">
<table class="fullWidth">
<tr>
<td>Area</td>
<td>
<form:select path="area" items="${areas}" class="fullWidth">
</form:select>
</td>
</tr>
<tr>
<td>Employee Name</td>
<td><form:input path="name" class="fullWidth"/></td>
</tr>
<tr>
<td colspan="2">
<input type="submit" value="Save Changes" id="btnSaveEmployee" class="fullWidth" />
</td>
</tr>
</table>
<!-- adding hidden field to hold id on update -->
<form:hidden path="id" />
</form:form>
控制器方法做驗證,要麼將一些錯誤或不
@RequestMapping(value = "/ajax", method = RequestMethod.POST)
protected @ResponseBody ValidationResponse createOrUpdate(
@Validated @ModelAttribute("employeeModel") Employee employee,
BindingResult bindingResult) {
if (!bindingResult.hasErrors()) {
employeeService.createOrUpdate(employee);
}
return validate(employee, null, bindingResult);
}
對於這個問題: 這一切工作正常,下拉填充,數據獲取填入投入。 但是當我點擊提交,我得到以下錯誤:
java.lang.IllegalStateException: Cannot convert value of type [java.lang.String] to required type [com.whatever.Area] for property 'area': no matching editors or conversion strategy found
據我瞭解,形式只是提交簡單的字符串「區」,而不是從列表中綁定的對象。
如何獲取表單提交對象而不是字符串?我的裝訂有問題嗎?
感謝您的幫助!
您可以發佈您的控制器方法,它映射URL「員工/ Ajax」的? – Jason 2012-08-01 09:32:13