嗨,在下面它返回成功的消息,但我沒有得到id,groupnames。 如何在下面的代碼中執行select查詢。我將記錄id和groupname的詳細信息。如何在php中顯示查詢記錄
任何一個可以幫助我
PHP
case "DispalyGroupDetails":
$userId = authenticateUser($db, $username, $password);
if ($userId != NULL)
{
if (isset($_REQUEST['username']))
{
$username = $_REQUEST['username'];
$sql = "select Id from users where username='$username' limit 1";
if ($result = $db->query($sql))
{
if ($row = $db->fetchObject($result))
{
$sql = "select g.id,g.groupname from `users` u, `friends` f,`group` g
where u.Id=f.providerId and f.providerId=g.providerId";
echo $sql;
if ($db->query($sql))
{
$out = SUCCESSFUL;
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED;
}
}
else
{
$out = FAILED;
}
break;
沒有必要那麼多,如果條件的,可以單用,如果檢查多個條件'&&'或''||等 – 2015-02-11 10:34:02
$ SQL =「從選擇g.id,g.groupname' users' U,'friends'樓'group'克 \t \t \t \t \t \t \t \t \t其中u.Id = f.providerId和f.providerId = g.providerId「; json格式如何執行查詢 – user1 2015-02-11 10:36:23