Spring MVC中，返回HTML

Question

這裏是我的控制器方法：

@RequestMapping(value = "/login/{id}", method = RequestMethod.GET) 
public String doLogin(@PathVariable long id, HttpServletRequest request, HttpServletResponse response, Model model) { 

logger.info(String.format(
       Constants.LogMessages.NEW_GET_REQUEST_FROM_IP, 
       request.getRemoteAddr())); 

logger.info("/login/{id}"); 

return "login"; 

} 

和我appServlet-context.xml中：

<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory --> 
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> 
    <beans:property name="prefix" value="/WEB-INF/views/" /> 
    <beans:property name="suffix" value=".html" /> 
</beans:bean> 

的例外，我在這個方法得到的是：

WARN PageNotFound - No mapping found for HTTP request with URI [/project/WEB-INF/views/login.html] in DispatcherServlet with name 'appServlet' 

事情是，當我將「後綴」更改爲.jsp和文件的名稱從HTML到.jsp它的作品。

有什麼想法爲什麼？

編輯：

這裏是我的web.xml：

<context-param> 

<param-name>contextConfigLocation</param-name> 

<param-value>/WEB-INF/spring/root-context.xml</param-value> 

<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> 

<servlet-name>appServlet</servlet-name> 

<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 

<init-param> 

    <param-name>contextConfigLocation</param-name> 

    <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value> 

</init-param> 

<load-on-startup>1</load-on-startup> 

<servlet-name>appServlet</servlet-name> 

<url-pattern>/</url-pattern> 

<filter-name>cors</filter-name> 

<filter-class>src.com.project.context.CorsFilter</filter-class> 

<filter-name>cors</filter-name> 

<url-pattern>/*</url-pattern> 

Answer 1

只是一個想法。可能是您的構建過程沒有將/project/WEB-INF/views/login.html文件複製到戰爭中。 Unwar並檢查是否存在。

Answer 2

在您的.xml文件，嘗試改變：

<servlet-name>appServlet</servlet-name> 

<url-pattern>/</url-pattern> 

要：

<servlet-name>appServlet</servlet-name> 

<url-pattern>*.html</url-pattern>