所需要的編碼工作不

Question

所需的腳本不工作

$("#s_postby").attr('required', false); // put the id of the input field that you whant required 
$("#s_postby").attr('required', true); // put the id of the input field that you whant required 

我在做的項目後我osclass主題的一些無線電場！

<div id="postby" class="property-ads-100"> 
     <label> 
     <span class="required_fields">*</span> 
     <?php _e('Posted By', 'ctg_housing'); ?> 
     </label> 
     <div class="item-post-postby-checkbox columns-0"> 
     <input type="radio" name="s_postby" value="owner" id="s_postby0" <?php if(isset($housing['s_postby']) && $housing['s_postby'] =='owner') { echo 'checked="checked"'; }; ?>> 
     <label for="s_postby0"> 
      <?php _e('Owner', 'ctg_housing'); ?> 
     </label> 
     </div> 
     <div class="item-post-postby-checkbox columns-0"> 
     <input type="radio" name="s_postby" value="agent" id="s_postby1" <?php if(isset($housing['s_postby']) && $housing['s_postby'] =='agent') { echo 'checked="checked"'; }; ?>> 
     <label for="s_postby1"> 
      <?php _e('Agent', 'ctg_housing'); ?> 
     </label> 
     </div> 
     <div class="item-post-postby-checkbox columns-0"> 
     <input type="radio" name="s_postby" value="broker" id="s_postby2" <?php if(isset($housing['s_postby']) && $housing['s_postby'] =='broker') { echo 'checked="checked"'; }; ?>> 
     <label for="s_postby2"> 
      <?php _e('Broker', 'ctg_housing'); ?> 
     </label> 
     </div> 
     <div class="item-post-postby-checkbox columns-0"> 
     <input type="radio" name="s_postby" value="agency" id="s_postby3" <?php if(isset($housing['s_postby']) && $housing['s_postby'] =='agency') { echo 'checked="checked"'; }; ?>> 
     <label for="s_postby3"> 
      <?php _e('Agency', 'ctg_housing'); ?> 
     </label> 
     </div> 
    </div> 

我把這個隱藏在一些類別上（腳本中的要求不起作用!!）爲什麼？

<script type="text/javascript"> 
$('#catId').change(function(){ 
    if($('#catId').val() == "28" || $('#catId').val() == "29" || 
$('#catId').val() == "30" || $('#catId').val() == "31") 
    { 
     $("#postby").hide(); // change Posted By with ID you give to the div 
    $("#s_postby").attr('required', false); // put the id of the input field that you whant required 
    }else 
    { 
     $("#postby").show(); // change Posted By with ID you give to the div 
    $("#s_postby").attr('required', true); // put the id of the input field that you whant required 
    } 
}); 
</script> 

我現在需要它來使這個無線電領域所需要的時候顯示，而不是需要溫隱藏！當顯示和要求我需要一個錯誤信息發佈者：這個領域是必需的！

希望有人能幫助我！

Answer 1

element.required = true; 

How to set HTML5 required attribute in Javascript?