讀取JSON文件並顯示其內容

我有我的Unix機器上的文件test.json它具有數據如下讀取JSON文件並顯示其內容

{ 
    "recordId" :10, 
    "recordName" : "RECORDS", 
    "records" : [ { 
    "field1" : 111, 
    "titleField" : 1, 
    "titleIDMap" : null, 
    "titleId" : 500, 
    "titleStartDate" : "2013-12-22T00:00:00.000+0000", 
    "titleEndDate" : "2013-12-03T00:00:00.000+0000", 
    "languageId" : 20 
    }] 
}

現在我正在寫的REST球衣客戶閱讀測試。 json並顯示如下輸出

public class RestWebServiceClient { 
    private static String BASE_URL="https://myUrl.com"; 
    public static void main(String[] args) { 

     JSONParser parser = new JSONParser(); 
     final String auth = "mfndfkndfkdnfkdnfdkfndkfndfkndkfndzxzxzxz=="; 
     try { 

      Object obj = parser.parse(new FileReader("/home/user/test.json")); 
      JSONObject jsonObject = (JSONObject) obj; 
      final String postData = "dataTobePosted"; 
      final String postResult = postJSONData(auth, BASE_URL+"/search",postData); 
      System.out.println("\n============postResponse============"); 
      System.out.println(postResult); 
      JSONObject issueObj = new JSONObject(postResult); 

     }  
     catch (AuthenticationException e){ 
      System.out.println("Username or Password wrong!"); 
      e.printStackTrace(); 

     } catch (JSONException e) { 
      System.out.println("Invalid JSON output"); 
      e.printStackTrace(); 
     } catch (ClientHandlerException e) { 
      System.out.println("Error invoking REST method"); 
      e.printStackTrace(); 
     } catch (FileNotFoundException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } catch (IOException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } catch (ParseException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } 

    } 

    private static String postJSONData(String auth, String url, String data) throws AuthenticationException, ClientHandlerException{ 
     Client client = Client.create(); 
     WebResource webResource = client.resource(url); 
     ClientResponse response = webResource.header("Authorization", "Basic " + auth).type("application/json") 
     .accept("application/json").post(ClientResponse.class, data); 
     int statusCode = response.getStatus(); 
     if (statusCode == 401) { 
      throw new AuthenticationException("Invalid Username or Password"); 
     } 
     return response.getEntity(String.class); 
    }

如何讀取test.json並顯示其內容？

來源

2014-01-09 Amit Sharad

爲recordId：

JSONObject jsonObject = (JSONObject) obj; 
String name = (String) jsonObject.get("recordId"); 
System.out.println(name);

爲records：

List<String> list = new ArrayList<String>();  
JSONArray jsonList = jsonObject.getJSONArray("records"); 
    for (int i = 0; i < jsonList.length(); i++) 
    list.add(jsonList.getString(i));

你records數據將裏面list對象

來源

2014-01-09 11:42:28

@Kamlesh_Arya 感謝什麼生根粉打印記錄 –

@ AmitSharad..updated我回答 –

@Kamlesh_Arya postJSONData的返回是什麼 –

讀取JSON文件並顯示其內容

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