PHP陣列樹狀結構DB樹結構

Question

我在PHP有一個數據結構來連接使用Telnet這樣的開關：

Array 
(
    [172.1.1.2] => Array 
     (
      [0] => Array 
       (
        [IP] => 172.1.1.1 
        [PlatformBrand] => dlink 
       ) 

      [1] => Array 
       (
        [IP] => 172.1.1.5 
        [PlatformBrand] => dlink 
       ) 

      [2] => Array 
       (
        [IP] => 172.1.1.7 
        [PlatformBrand] => dlink 
       ) 

      [3] => Array 
       (
        [IP] => 172.1.1.8 
        [PlatformBrand] => dlink 
       ) 

     ) 

    [172.1.1.6] => Array 
     (
      [0] => Array 
       (
        [IP] => 172.1.1.10 
        [PlatformBrand] => dlink 
       ) 
     ) 

    [172.1.1.7] => Array 
     (
      [0] => Array 
       (
        [IP] => 172.1.1.11 
        [PlatformBrand] => dlink 
       ) 
      [1] => Array 
       (
        [IP] => 172.1.1.14 
        [PlatformBrand] => dlink 
       ) 
     ) 
) 

但我想轉換成樹這個像這樣的結構：

CREATE TABLE `network_equipment_class` (
    `id` int(11) NOT NULL, 
    `ip` varchar(15) NOT NULL, 
    `parent` int(11) NOT NULL, 
    `sort` int(11) NOT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=utf8; 

id | ip   | parent | sort 
-------------------------------- 
1 | 172.1.1.2 | 0  | 0 
2 | 172.1.1.1 | 1  | 0 
3 | 172.1.1.5 | 1  | 1 
4 | 172.1.1.7 | 1  | 2 
5 | 172.1.1.8 | 1  | 3 
6 | 172.1.1.6 | 0  | 1 
7 | 172.1.1.10 | 6  | 0 
8 | 172.1.1.11 | 4  | 0 
9 | 172.1.1.14 | 4  | 1 

對於PHP> = 5.3來書寫功能代碼，任何想法或任何建議？

UPDATE： 這裏是我寫的代碼，但不能使用：

function createDBTree($IP, $dbTree){ 
    if (!is_array($dbTree) || $dbTree == array()) { 
     $dbTree = array('ip' => $IP); 
    } else { 
     foreach ($dbTree as $dbkey => $tmpdbvalue) { 
      if(is_array($tmpdbvalue) && $arr !== array()) { 
       if (!isset($tmpdbvalue['children'])) $dbTree = $this->createDBTree($IP, $tmpdbvalue['children']); 
      } else { 
       if ($tmpdbvalue['ip'] == $IP) $tmpdbvalue['children'] = array('ip' => $IP); 
      } 
     } 
    } 

    return $dbTree; 
} 

最後，我將完成結構：

172.1.1.2 => 172.1.1.1 
      => 172.1.1.5 
      => 172.1.1.7 => 172.1.1.11 => ... => ... 
          => 172.1.1.14 
          => ... 
      => 172.1.1.8 
      => ... 

172.1.1.6 => 172.1.1.10 
      => ... 

... 

Answer 1

使用本。

$arr = array('172.1.1.2' => array(
           array('IP' => '172.1.1.1','PlatformBrand' => 'dlink'), 
           array('IP' => '172.1.1.5','PlatformBrand' => 'dlink'), 
           array('IP' => '172.1.1.7','PlatformBrand' => 'dlink'), 
           array('IP' => '172.1.1.8','PlatformBrand' => 'dlink') 
          ), 
      '172.1.1.6' => array(
           array('IP' => '172.1.1.10','PlatformBrand' => 'dlink') 
          ), 
      '172.1.1.7' => array(
           array('IP' => '172.1.1.11','PlatformBrand' => 'dlink'), 
           array('IP' => '172.1.1.14','PlatformBrand' => 'dlink') 
          ),         
      );     
$sn = $parent = $sort = 0; 
$hdr = "id | ip | parent | sort\r\n"; 
$hdr .= "--------------------------------\r\n"; 
foreach($arr as $k => $v){ 
    $sn++; 
    $hdr .= "$sn | $k | $parent | $sort \r\n"; 
    $parent = $sn; 
    foreach($v as $t => $d){ 
    $sn++; 
    $hdr .= "$sn | {$d['IP']} | $parent | $sort \r\n"; 
    $sort++; 
    } 
    $parent = 0; 
    $sort = 0; 
} 

echo nl2br($hdr); 

記住，你在你的問題有陣列的輸出，所以你必須把它格式化成PHP數組你迭代它之前。

如果您正在寫入數據庫，您當然不需要換行符"\n\r"和nl2br。只需在循環中構建查詢並執行即可。