0
我正在使用Swagger爲我的一個Spring Rest API項目創建API文檔，但創建的swagger.json文件存在問題。 我的一個超級班級沒有正確轉換。Swagger Java類不能正確解析
用於實施招搖的圖書館是springfox。請在下面找到實施細節。
配置 EnableWebMvc EnableSwagger2 ComponentScan
public class MvcConfig extends WebMvcConfigurerAdapter {
}
這是類引起的問題
public class ListResultModel MODEL extends BaseModel {
}
的Json創建
"schema":{"$ref":"#/definitions/RedirectAttributes"}}],"responses":{"200":{"description":"OK","schema":{"type":"string"}},"201":{"description":"Created"},"401":{"description":"Unauthorized"},"403":{"description":"Forbidden"},"404":{"description":"Not Found"}}}},"/admin/migration/vat":{"get":{"tags":["migration-controller"],"summary":"vatMigration","operationId":"vatMigrationUsingGET","consumes":["application/json"],"produces":["/"],"parameters":[{"name":"retailerId","in":"query","description":"retailerId","required":true,"type":"string"}
{"$ref":"#/definitions/**ListResultModel«Item»"**}},"401":{"description":""},"403":{"description":"Forbidden"},"404":{"description":"Not Found"}}}},"/api/items/withoutPictures/{departmentId}/{vendorId}/{status}":{"200":{"description":"OK","schema":{"$ref":"#/definitions/**ListResultModel«Item»"}**},"401":{"description":""},"403":{"description":"Forbidden"},"404":{"description":"Not }
{"$ref":"#/definitions/ListResultModel«Lead»"}},"201":{"description":"Created"},"401":{"description":""},"403":{"description":"Forbidden"},"404":{"description":"Not Found"}}}}
我正在努力解決這個問題很長一段時間，沒有線索如何去做。請任何人都可以幫助我！
在此先感謝。 Vivek
什麼是您所遇到的錯誤？你能詳細說明這個問題嗎？ –
Hi Bandi Kishore， 感謝您的幫助。 ListResultModel«Item»不是一個有效的json符號，它應該轉換爲json格式。我正在使用生成的json將API導入到Amazone中（https://aws.amazon.com/about-aws/whats-new/2015/07/introducing-swagger-importer-easily-import-swagger-api-定義成amazon-api-gateway /），並且由於json中的以下符號而失敗 「 Regards Vivek – Vivek