XML - 針對節點屬性，推入Flash AS3陣列

Question

我試圖將每個「問題」標籤中的「txt」屬性的內容推入AS3 Flash中名爲「questions」的數組中。這是我的xml文件的摘錄。

<question id='Q1' uId='99036' no_ans='2' txt='In a flat structure employees are not expected to provide their bosses with their opinions.' feedback='' type='MC' passingWeight='1' url='media/'> 
    <answer id='Q1A1' uId='311288' txt='True' weight='0'/> 
    <answer id='Q1A2' uId='311289' txt='False' weight='1'/> 
</question> 
<question id='Q2' uId='99037' no_ans='2' txt='In a hierarchy, information typically flows downward.' feedback='' type='MC' passingWeight='1' url='media/'> 
    <answer id='Q2A1' uId='311290' txt='True' weight='1'/> 
    <answer id='Q2A2' uId='311291' txt='False' weight='0'/> 
</question> 
<question id='Q3' uId='99038' no_ans='2' txt='Someone who keeps many projects going at one time is an example of someone who is flexible-time oriented.' feedback='' type='MC' passingWeight='1' url='media/'> 
    <answer id='Q3A1' uId='311292' txt='True' weight='1'/> 
    <answer id='Q3A2' uId='311293' txt='False' weight='0'/> 
</question> 

這是我在一個循環的嘗試：

// get number of questions 
    trace(myXML.question.length()); 
    numberOfQuestions = myXML.question.length(); 

    //loop and push questions into questions array at top 
    for (var i:int = 0; i < numberOfQuestions; i++) { 
     trace("Hello."); 
     questions.push(myXML.question.@txt); 
     trace(questions); 
    } 

這只是推的問題，所有9日一旦進入陣列的每個位置。我想每個陣列位置1個問題。我不確定如何在問題標記中使用id屬性來區分每個問題。

編輯：我嘗試這樣做，我可以從的processXML函數中（2）訪問使用getQuestionAt問題文本，但不應超出它。

var myXML:XML; 
var myLoader:URLLoader = new URLLoader(); 
myLoader.load(new URLRequest("html/VUBZ7318CROSSCULTUREQUIZ/manifest.xml")); 
myLoader.addEventListener(Event.COMPLETE, processXML); 
function processXML(e:Event):void { 
    myXML = new XML(e.target.data); 

    //trace(myXML.question) 

    // get number of questions 
    trace(myXML.question.length()); 
    numberOfQuestions = myXML.question.length(); 

    //Question list 
    var questions:Object = {}; 
    //Extracting question from xml 
    for each (var item:XML in myXML.question) { 
     questions[item. @ id] = item. @ txt; 
    } 
    //Some method for fetching question from question list 
    function getQuestionAt(index:Number):String { 
     if (questions["Q" + index] == undefined) { 
      throw new Error("Wrong index for question!!!"); 
     } 
     return questions["Q"+index]; 
    } 

    //Getting question from list 
    trace("Here is question No 2:\t" + getQuestionAt(2)); 


} 

Answer 1

創建只有一個幀的新層，並且只要您的總幀數（例如6個長），就創建該幀的長度。然後把這個代碼放在那個框架中。

//Question list 
var questions:Object; 
//Some method for fetching question from question list 
function getQuestionAt(index:Number):String{ 
    if(questions["Q"+index] == undefined){ 
     throw new Error("Wrong index for question!!!"); 
    } 
    return questions["Q"+index]; 
}  

然後，每當你想提問添加這些行到您的processXML功能

function processXML():*{ 
//.....Your 'myXML' is here.... 
questions = {}; 
//Extracting question from xml 
for each(var item:XML in myXML.question){ 
    questions[item.@id] = item.@txt; 
} 
} 

呼叫getQuestionAt。您可以在任何框架中調用該功能，因爲它在所有框架上都是「可見的」。

Answer 2

您的XML設置只是一個錯誤。在AS3中，你需要一個根節點。根節點不可訪問，它只是一種包裝。在你的情況下，問題是你的根節點不可訪問，這將使這些屬性無法訪問。所以把你的XML包裝。我可能是錯誤的無法訪問根節點屬性，但我對你的XML是正確的。而添加包裝只是使得更容易。

<questions> 
    <question id='Q1' uId='99036' no_ans='2' txt='In a flat structure employees are not expected to provide their bosses with their opinions.' feedback='' type='MC' passingWeight='1' url='media/'> 
     <answer id='Q1A1' uId='311288' txt='True' weight='0'/> 
     <answer id='Q1A2' uId='311289' txt='False' weight='1'/> 
    </question> 
    <question id='Q2' uId='99037' no_ans='2' txt='In a hierarchy, information typically flows downward.' feedback='' type='MC' passingWeight='1' url='media/'> 
     <answer id='Q2A1' uId='311290' txt='True' weight='1'/> 
     <answer id='Q2A2' uId='311291' txt='False' weight='0'/> 
    </question> 
    <question id='Q3' uId='99038' no_ans='2' txt='Someone who keeps many projects going at one time is an example of someone who is flexible-time oriented.' feedback='' type='MC' passingWeight='1' url='media/'> 
     <answer id='Q3A1' uId='311292' txt='True' weight='1'/> 
     <answer id='Q3A2' uId='311293' txt='False' weight='0'/> 
    </question> 
</questions> 

然後像這樣獲取屬性。

var questions:XMLList = new XMLList(e.target.data.question) 
for each (var question:XML in questions){ 
    trace(question.@txt) 
} 

Answer 3

你有什麼不是XML，而是一個XMLList，它是完全可以接受的。

你不需要循環。你可以像這樣得到另一個XMLList。 XMLList就像一個XML數組，但在這種情況下，您將不會有完全形成的節點，而只是所有屬性的內容。

它會是這樣的：

var questionTxt:XMLList = yourQuestions.@txt;//yourQuestions contains your originalXMLList as shown above 

現在，您可以訪問每一個文本元素爲：

var stem:String = String(questionTxt[0]); 

如果由於某種原因，你絕對必須有一個數組，您可以這樣做：

var questions:Array = new Array(); 
for (var i:int = 0; i< questionTxt.length(); i++) { 
    questions[i] = questionTxt[i]; 
} 

但是，它看起來像很多o因爲你可以簡單地使用XMLList，就像通過e4x訪問它一樣。你的全部目標是什麼？

我只是看着你的問題多一點細心，你真正需要做的是這樣的：

protected var questions:XMLList; 
public function processXML(e:Event):void { 
      myXML = XML(e.target.data); 
      questions = myXML.question; 

      // get number of questions 
      trace(myXML.question.length()); 
} 

public function getQuestionAt(index:Number):String { 
      if (questions[index] == undefined) { 
       throw new Error("Wrong index for question!!!"); 
      } 
      return questions[index].attribute('txt'); 
}  

public function get numberOfQuestions():int { 
    return myXML.question.length(); 
}