我發現本指南中試圖完成類似的東西非常有用:
https://www.dashingd3js.com/svg-text-element
基於以上鍊接這段代碼生成圈子標籤:如果你想成長的
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="http://d3js.org/d3.v3.min.js" charset="utf-8"></script>
</head>
<body style="overflow: hidden;">
<div id="canvas" style="overflow: hidden;"></div>
<script type="text/javascript">
var graph = {
"nodes": [
{name: "1", "group": 1, x: 100, y: 90, r: 10 , connected : "2"},
{name: "2", "group": 1, x: 200, y: 50, r: 15, connected : "1"},
{name: "3", "group": 2, x: 200, y: 130, r: 25, connected : "1"}
]
}
$(document).ready(function() {
var width = 2000;
var height = 2000;
var svg = d3.select("#canvas").append("svg")
.attr("width", width)
.attr("height", height)
.append("g");
var lines = svg.attr("class", "line")
.selectAll("line").data(graph.nodes)
.enter().append("line")
.style("stroke", "gray") // <<<<< Add a color
.attr("x1", function (d, i) {
return d.x
})
.attr("y1", function (d) {
return d.y
})
.attr("x2", function (d) {
return findAttribute(d.connected).x
})
.attr("y2", function (d) {
return findAttribute(d.connected).y
})
var circles = svg.selectAll("circle")
.data(graph.nodes)
.enter().append("circle")
.style("stroke", "gray")
.style("fill", "white")
.attr("r", function (d, i) {
return d.r
})
.attr("cx", function (d, i) {
return d.x
})
.attr("cy", function (d, i) {
return d.y
});
var text = svg.selectAll("text")
.data(graph.nodes)
.enter()
.append("text");
var textLabels = text
.attr("x", function(d) { return d.x; })
.attr("y", function(d) { return d.y; })
.text(function (d) { return d.name })
.attr("font-family", "sans-serif")
.attr("font-size", "10px")
.attr("fill", "red");
});
function findAttribute(name) {
for (var i = 0, len = graph.nodes.length; i < len; i++) {
if (graph.nodes[i].name === name)
return graph.nodes[i]; // Return as soon as the object is found
}
return null; // The object was not found
}
</script>
</body>
</html>
儘管此鏈接可能會回答問題,但最好在此處包含答案的基本部分,並提供供參考的鏈接。如果鏈接頁面更改,則僅鏈接答案可能會失效。 – Whymarrh
@Whymarrh答案已更新 –