忽略JAXB內部元素

Question

我有一些使用JAXB處理的XML。我不明白爲什麼我不能訪問這個標籤的內部元素。

XML片段：

<binary> 
    <route> 
     <payload source="SomeService" version="1.2"><![CDATA[ACAA8f///...snip...AAAAAGGAAAARAFR]]> 
     </payload> 
    </route> 
</binary> 

由此我產生了XSD：

<xsd:element name="binary"> 
     <xsd:complexType> 
     <xsd:sequence> 
      <xsd:element name="route"> 
      <xsd:complexType> 
       <xsd:sequence> 
       <xsd:element name="payload"> 
        <xsd:complexType> 
        <xsd:attribute name="source" type="xsd:string" /> 
        <xsd:attribute name="version" type="xsd:string" /> 
        </xsd:complexType> 
       </xsd:element> 
       </xsd:sequence> 
      </xsd:complexType> 
      </xsd:element> 
     </xsd:sequence> 
     </xsd:complexType> 
    </xsd:element> 

我使用maven-JAXB2-插件，一切運作良好：

<build> 
    <plugins> 
     <plugin> 
     <inherited>true</inherited> 
     <groupId>org.apache.maven.plugins</groupId> 
     <artifactId>maven-compiler-plugin</artifactId> 
     <configuration> 
      <source>1.6</source> 
      <target>1.6</target> 
     </configuration> 
     </plugin> 
     <plugin> 
     <groupId>org.jvnet.jaxb2.maven2</groupId> 
     <artifactId>maven-jaxb2-plugin</artifactId> 
     <executions> 
      <execution> 
      <goals> 
       <goal>generate</goal> 
      </goals> 
      </execution> 
     </executions> 
     </plugin> 
    </plugins> 
</build> 

在我對象，我有方法getSource（）和getVersion（）但沒有getValue（）或沿着這些線的東西。我從根本上失去了一些東西？試圖以這種方式訪問​​內部元素數據不正確？

編輯：包括生成的Java代碼

/** 
     * <p>Java class for anonymous complex type. 
     * 
     * <p>The following schema fragment specifies the expected content contained within this class. 
     * 
     * <pre> 
     * &lt;complexType> 
     * &lt;complexContent> 
     *  &lt;restriction base="{http://www.w3.org/2001/XMLSchema}anyType"> 
     *  &lt;attribute name="source" type="{http://www.w3.org/2001/XMLSchema}string" /> 
     *  &lt;attribute name="version" type="{http://www.w3.org/2001/XMLSchema}string" /> 
     *  &lt;/restriction> 
     * &lt;/complexContent> 
     * &lt;/complexType> 
     * </pre> 
     * 
     * 
     */ 
     @XmlAccessorType(XmlAccessType.FIELD) 
     @XmlType(name = "") 
     public static class Payload { 

      @XmlAttribute(name = "source") 
      protected String source; 
      @XmlAttribute(name = "version") 
      protected String version; 
      @XmlValue 
      protected String value; 
      /** 
      * Gets the value of the source property. 
      * 
      * @return 
      *  possible object is 
      *  {@link String } 
      *  
      */ 
      public String getSource() { 
       return source; 
      } 

      /** 
      * Sets the value of the source property. 
      * 
      * @param value 
      *  allowed object is 
      *  {@link String } 
      *  
      */ 
      public void setSource(String value) { 
       this.source = value; 
      } 

      /** 
      * Gets the value of the version property. 
      * 
      * @return 
      *  possible object is 
      *  {@link String } 
      *  
      */ 
      public String getVersion() { 
       return version; 
      } 

      /** 
      * Sets the value of the version property. 
      * 
      * @param value 
      *  allowed object is 
      *  {@link String } 
      *  
      */ 
      public void setVersion(String value) { 
       this.version = value; 
      } 

     } 

Answer 1

的​​元素的模式定義看起來應該像下面讓你正在尋找的JAXB類。您需要修復如何從XML文檔生成XML模式。

<element name="payload"> 
    <complexType> 
     <simpleContent> 
      <extension base="string"> 
       <xsd:attribute name="source" type="xsd:string" /> 
       <xsd:attribute name="version" type="xsd:string" /> 
      </extension> 
     </simpleContent> 
    </complexType> 
</element> 

更多信息

• http://blog.bdoughan.com/2011/06/jaxb-and-complex-types-with-simple.html