如何從下拉菜單中爲多個表在數據庫中插入選定的數據

Question

這是我的register.php（形式）：

<table width="350" border="0"> 
    <center><tr> 
    <td><form action="newregister.php" method="post"> 
    Nama</td> 
    <td> : </td> 
    <td></td> 
    <td width="200"><center><input name="nama_pelajar" type="text"></center></td> 
    </tr> 
    <tr> 
    <td>No Kad Pengenalan</td> 
    <td> : </td> 
    <td></td> 
    <td><center><input name="ic_pelajar" type="text"></center></td></tr> 
    <tr> 
    <td>ID Pelajar</td> 
    <td> : </td> 
    <td></td> 
    <td><center><input name="id_pelajar" type="text"></td> 
    </tr> 
    <tr> 
    <td><br>Sesi</td> 
    <td> : </td> 
    <td></td> 
    <td><center><select name="sesi"> 
     <option><center>-Sila pilih-</option> 
     <option value="Jun 14">Jun 2014</option> 
     <option value="Dis 14">Dis 2014</option> 
     <option value="Jun 15">Jun 2015</option> 
     <option value="Dis 15">Dis 2015</option> 
     <option value="Jun 16">Jun 2016</option> 
     <option value="Dis 16">Dis 2016</option> 
     <option value="Jun 17">Jun 2017</option> 
     <option value="Dis 17">Dis 2017</option> 
     </select> 
    </td> 
    </tr> 
    <tr> 
    <td><br>Kursus</td> 
    <td> : </td> 
    <td></td> 
    <td><center><select name="kursus"> 
     <option>-Sila pilih-</option> 
     <option value="Senibina">Kursus Lukisan Seni Bina</option> 
     <option value="Elektrik">Kursus Pemasangan Elektrik</option> 
     <option value="Fesyen">Kursus Fesyen &amp; Pakaian</option> 
     <option value="Makanan">Kursus Pemprosesan Makanan</option> 
    </select></td> 
    </tr> 
    <tr> 
    <td><br>No Telefon</td> 
    <td> : </td> 
    <td></td> 
    <td><center><input name="no_tel" type="text"></td> 
    </tr> 
    <tr> 
    <td><br>Email</td> 
    <td> : </td> 
    <td></td> 
    <td><center><input name="email" type="text"></td> 
    </tr> 
    <tr> 
    <td><center><input name="" type="submit" value="Simpan"> 
    <input name="" type="reset" value="Set Semula"> 
    </center> 
    </form> 

    </td> 
    </tr> 

</table> 

，這是我的PHP代碼（newregister.php）：

<?php 

require_once "conn.php"; 
    $conn = connect(); 
    $db = connectdb(); 
mysql_select_db($db,$conn) or die (mysql_error() . "\n"); 

$query_usr = "select * from register_jun14"; 
$usr = mysql_query($query_usr,$conn) or die(mysql_error()."\n".$query_usr); 
$row_usr=mysql_fetch_assoc($usr); 

$nama_pelajar=$_REQUEST["nama_pelajar"]; 
$ic_pelajar=$_REQUEST["ic_pelajar"]; 
$id_pelajar=$_REQUEST["id_pelajar"]; 
$sesi=$_REQUEST["sesi"]; 
$kursus=$_REQUEST["kursus"]; 
$no_tel=$_REQUEST["no_tel"]; 
$email=$_REQUEST["email"]; 

$query = "INSERT INTO register_jun14(nama_pelajar,ic_pelajar,id_pelajar,sesi,kursus,no_tel,email) VALUES ('$nama_pelajar','$ic_pelajar', 
'$id_pelajar','$sesi','$kursus','$no_tel','$email')"; 
$result = mysql_query($query); 

echo "<script languange = 'Javascript'> 
       alert('Pendaftaran berjaya!'); 
       location.href = 'register.php';</script>"; 

?> 

我的問題：

如何INS如果有「Jun14」，「Dis14」，「Jun15」，「Dis15」等表格，選擇「sesi」（下拉菜單）到數據庫的新表格中？

有人嗎？

Answer 1

我假設你想選擇根據自己的下拉選擇在此框中表（意味着你有多個表jun14，dis14，jun15等）

<td><center><select name="sesi"> 
     <option><center>-Sila pilih-</option> 
     <option value="Jun 14">Jun 2014</option> 
     <option value="Dis 14">Dis 2014</option> 
     <option value="Jun 15">Jun 2015</option> 
     <option value="Dis 15">Dis 2015</option> 
     <option value="Jun 16">Jun 2016</option> 
     <option value="Dis 16">Dis 2016</option> 
     <option value="Jun 17">Jun 2017</option> 
     <option value="Dis 17">Dis 2017</option> 
     </select> 
    </td> 

首先你需要改變上述這樣

//you should remove the space and add underscore in order for your query to work 
//for the if statement 
<td><center><select name="sesi"> 
     <option><center>-Sila pilih-</option> 
     <option value="jun_14">Jun 2014</option> 
     <option value="dec_14">Dis 2014</option> 
     <option value="Jun_15">Jun 2015</option> 
     <option value="Dis_15">Dis 2015</option> 
     <option value="Jun_16">Jun 2016</option> 
     <option value="Dis_16">Dis 2016</option> 
     <option value="Jun_17">Jun 2017</option> 
     <option value="Dis_17">Dis 2017</option> 
     </select> 
    </td> 

部分我刪除的價值空間，並添加像6月14日成爲一個jun_14下劃線，12月14日成爲十二月_14等，

現在你[R newregister PHP應該是這樣的

<?php 
//i remove your this line assuming these lines you are connecting with your database these lines i removed 
//require_once "conn.php"; 
//$conn = connect(); 
// $db = connectdb(); 
//mysql_select_db($db,$conn) or die (mysql_error() . "\n"); 

     //and i added this line instead in this line i am also connecting 
//with database 
    $conn= mysqli_connect('localhost', 'root', 'yourpassword', 'yourdatabasename') 
or die(mysqli_error($con)); 



    $query_usr = "select * from register_jun14"; 
    //$usr = mysql_query($query_usr,$conn) or die(mysql_error()."\n".$query_usr); 

    $usr = mysqli_query($conn,$query_usr) or die(mysqli_error()."\n".$query_usr); 
    $row_usr=mysqli_fetch_assoc($usr); 

    $nama_pelajar=$_REQUEST["nama_pelajar"]; 
    $ic_pelajar=$_REQUEST["ic_pelajar"]; 
    $id_pelajar=$_REQUEST["id_pelajar"]; 
    $sesi=$_REQUEST["sesi"]; 
    $kursus=$_REQUEST["kursus"]; 
    $no_tel=$_REQUEST["no_tel"]; 
    $email=$_REQUEST["email"]; 


    if($sesi=="jun_14") 
    { 
    //assuming you have Jun14 table in your database with same field as your 
    //original insert query in the question 

     $query = "INSERT INTO Jun14(id, nama_pelajar,ic_pelajar,id_pelajar,sesi,kursus,no_tel,email) VALUES ('','$nama_pelajar','$ic_pelajar', 
    '$id_pelajar','$sesi','$kursus','$no_tel','$email')"; 
    $result = mysqli_query($conn,$query) or die(mysqli_error($conn)); 
    } 

    if($sesi=="dec_14") 
    { 
    //assuming you have Dis14 table in your database with same field as your 
     //original insert query in the question 

     $query = "INSERT INTO Dis14(id, nama_pelajar,ic_pelajar,id_pelajar,sesi,kursus,no_tel,email) VALUES ('','$nama_pelajar','$ic_pelajar', 
    '$id_pelajar','$sesi','$kursus','$no_tel','$email')"; 
    $result = mysqli_query($conn,$query) or die(mysqli_error($conn)); 
    } 

if($sesi=="jun_15") 
    { 


//assuming you have Jun15 table in your database with same field as your 
//original insert query in the question 
     $query = "INSERT INTO Jun15(id, nama_pelajar,ic_pelajar,id_pelajar,sesi,kursus,no_tel,email) VALUES ('','$nama_pelajar','$ic_pelajar', 
    '$id_pelajar','$sesi','$kursus','$no_tel','$email')"; 
    $result = mysqli_query($conn,$query) or die(mysqli_error($conn)); 
    } 
    //i am leaving this your query here i dont know why you need it, may be you 
//need it 
    $query = "INSERT INTO register_jun14 (nama_pelajar,ic_pelajar,id_pelajar,sesi,kursus,no_tel,email) VALUES ('$nama_pelajar','$ic_pelajar', 
    '$id_pelajar','$sesi','$kursus','$no_tel','$email')"; 
    $result = mysqli_query($conn,$query) or die(mysqli_error($conn)); 

您可以進一步寫，如果按照下拉菜單 你的價值主張中可以添加如果你想爲了實現自己的目標的條件儘可能多的下拉菜單中，爲什麼你正在運行選擇查詢我不知道。