刪除標點符號java

Question

我試圖從字符串中刪除標點符號，但保留空格，因爲我需要能夠區分不同的單詞。最終目標是找出字符串中每個單詞的長度。

我設置了一個for循環來檢查單詞的長度，直到它遇到空格爲止，但這會將標點符號計爲一個字母。我知道我必須更改if語句中的變量，以反映字符串中空格的i和indexOf之間的子字符串的長度。

for(int i=0; i > stringLength - 1;){ 
original.substring(i, original.indexOf(' ')); 
if(i > minLength) 

Answer 1

雖然它可能是誘人拋出一堆維權的和IFS，這將是清潔劑只使用正則表達式：

Pattern.compile("[.,; ]+").splitAsStream(input) 

完整的例子：

import java.util.regex.Pattern; 
import java.util.stream.Collectors; 

public class Counting { 
    public static void main(String... args) { 
     String text = "This is a string. With some punctuation, but I only care about words."; 

     String wordsWithLengths = Pattern.compile("[.,; ]+") 
       .splitAsStream(text) 
       .map(word -> word + " => " + word.length()) 
       .collect(Collectors.joining("\n")); 

     System.out.println(wordsWithLengths); 
    } 
} 

輸出：

This => 4 
is => 2 
a => 1 
string => 6 
With => 4 
some => 4 
punctuation => 11 
but => 3 
I => 1 
only => 4 
care => 4 
about => 5 
words => 5 

另外，如果你想算多少的話有N多角色越多，你可以：

import java.util.regex.Pattern; 

public class CountingWords { 
    public static void main(String... args) { 
     String text = "This is a string. With some punctuation, but I only care about words."; 

     int threshold = 5; 
     long amountOfWords = Pattern.compile("[.,; ]+") 
       .splitAsStream(text) 
       .filter(word -> word.length() > threshold) 
       .count(); 

     System.out.println("There are " + amountOfWords + " words with more than " + threshold + " characters"); 
    } 
} 

Answer 2

如果您只是需要得到每個字比這個會做的長度，否則，你這樣做opertaion中如果statment：

int cnt = 0; 
for(int i=0; i < original.length();i++){ 
    if(",;:.?! ".indexOf(orignal.charAt(i)) > -1){ 
     if(cnt > 0){ 
      System.out.println(cnt); 
      cnt = 0; 
     } 
    } else { 
     cnt++; 
    } 
}