1
這是我的views.py問題將數據保存到數據庫
def signup(request):
print "signup"
if request.method == 'POST':
print "post signup"
form = RegisterForm(request.POST)
try:
if form.is_valid():
print form.cleaned_data
u = User.objects.create_user(form.cleaned_data['emailid'], form.cleaned_data['emailid'], form.cleaned_data['passwd1'])
ui = UserInfo()
ui.user = u
ui.class_of = form.cleaned_data['gradyear']
ui.grade = form.cleaned_data['grade']
ui.balance = 0
ui.save()
,並在我的forms.py我有:
class RegisterForm(forms.Form):
GRADE_CHOICES = (
(9,'9'), (10,'10'), (11,'11'), (12,'12') ,
)
curr_year = date.today().year
GRAD_YEAR_CHOICES = (
(curr_year,curr_year), (curr_year+1,curr_year+1), (curr_year+2,curr_year+2), (curr_year+3,curr_year+3) ,
)
first_name = forms.CharField(max_length = 25)
last_name = forms.CharField(max_length = 25)
emailid = forms.EmailField()
passwd1 = forms.CharField(max_length=100,widget=forms.PasswordInput)
passwd2 = forms.CharField(max_length=100,widget=forms.PasswordInput)
gradyear = forms.ChoiceField(choices=GRAD_YEAR_CHOICES)
grade = forms.ChoiceField(choices=GRADE_CHOICES)
def clean(self):
cleaned_data = super(RegisterForm, self).clean()
if cleaned_data['passwd1'] != cleaned_data['passwd2']:
raise forms.ValidationError({'passwd1':['Password do not match']})
if User.objects.filter(email=cleaned_data['emailid']).count():
raise forms.ValidationError({'emailid':['Email already taken ']})
return cleaned_data
爲什麼一切打印到數據庫除了FIRST_NAME和姓氏? ? (用戶名,電子郵件,等級,gradyear和密碼都保存)
編輯:這是我的UserInfo
class UserInfo(models.Model):
user = models.OneToOneField(User, related_name='user_infos')
class_of = models.IntegerField()
#username = user.username
#fname = user.fname
#lname = user.last_name
#email = user.email
#Staff = user.is_staff
pub_date = models.DateTimeField(auto_now=True)
grade = models.IntegerField()
balance = models.DecimalField(max_digits=6, decimal_places=2)
#first_name = models.CharField(max_length = 25)
是什麼用戶信息模型是什麼樣子? – user1797792
只需添加'User.objects.create_user(first_name = form.cleaned_data ['first_name'],...' – sobolevn
我想將它添加到數據庫中,而不是使其成爲登錄用戶的一部分@sobolevn –