1
它可能有兩個類Template
和TemplateItem
,映射到兩個數據庫表template
和template_item
,它們使用Map<String, TemplateItem>
?如果是這樣,可以使用註釋完成?存儲沒有映射表的JSP HashMap?
以下結果在三個表中,即添加一個不必要的映射表。
@Entity
@Table(name = "template")
public class Template {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name="id")
private long id = 0;
@Column(name="name")
private String name = "";
// Left side of map maps to name field of the item on the right side of the map.
@OneToMany(cascade=CascadeType.ALL, fetch=FetchType.LAZY)
@MapKey(name = "name")
private Map<String, TemplateItem> items = new HashMap<String, TemplateItem>();
}
@Entity
@Table(name = "template_item")
public class TemplateItem {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name="id")
private long id = 0;
// The name field is the unique key for the Template.items Map
@Column(name="name")
private String name = "";
@ManyToOne(cascade=CascadeType.ALL, fetch=FetchType.LAZY)
private Template template;
@Column(name="content")
private String content = "";
}
在MySQL中,我們得到了三個表,映射表包含兩列複製出TemplateItem表:
+-------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+--------------+------+-----+---------+----------------+
| id | bigint(20) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | NO | UNI | NULL | |
+-------------+--------------+------+-----+---------+----------------+
+-------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+--------------+------+-----+---------+----------------+
| id | bigint(20) | NO | PRI | NULL | auto_increment |
| content | longtext | NO | | NULL | |
| name | varchar(120) | NO | | NULL | |
| template_id | bigint(20) | YES | MUL | NULL | |
+-------------+--------------+------+-----+---------+----------------+
+----------------+------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+----------------+------------+------+-----+---------+-------+
| at_template_id | bigint(20) | NO | PRI | NULL | |
| items_id | bigint(20) | NO | PRI | NULL | |
+----------------+------------+------+-----+---------+-------+
使用連接表有什麼問題?這是規範化模式的一種非常標準的方式。 – 2010-09-01 22:48:55
它是完全多餘的。自動創建的連接表有兩個字段,這兩個字段已存儲在'TemplateItem'類中。 – Jacob 2010-09-01 22:50:42