2
我有如下代碼,這讓$_GET
和控制器,動作做除法,而params友好的URL與 「:」
http://localhost/controller/action/param1/param2
$url = explode('/', $_GET['url']);
$urlSize = count($url);
$filter = $this->factory('Core\Security\Filter');
if($urlSize >= 1) {
$controller = $filter->replace($url[0], 'friendly-url');
if($urlSize >= 2) {
$action = $filter->replace($url[1], 'friendly-url');
if($urlSize >= 3) {
unset($url[0], $url[1]);
foreach($url as $index => $param) {
$params[] = $filter->replace($param, 'friendly-url');
}
}
}
}
Core\Security\Filter->replace()
這我現在正在開發:
public function replace($data = null, $type = 'alphanumeric') {
/*
@TODO, implement regex by type
numeric
$regex = '/^[[:digit:]]$/';
alphanumeric
$regex = '/^[[:alnum:]]$/';
friendly-url
$regex = '/[^a-zA-Z0-9_-]+/';
$replace = '-'
username
$regex = '/^[^a-zA-Z0-9_-.]{3,32}+';
email
$regex = '/^[[a-zA-Z0-9_-.]{1,96}][email protected][a-zA-Z0-9-]{2,64}+(?:\.[a-zA-Z0-9-]+)*$/';
*/
}
好,我的問題是:如何獲得這種格式的網址:
http://localhost/controller/action/param1/param2:value2
$參數數組:
Array(
[0] => param1
[1] => Array(
[param2] => value2
)
)
解決這一點:在上面使用
foreach($url as $index => $param) {
if(strstr($param, ':')) {
$subParam = explode(':', $param, 2);
$this->_request['params'][][$subParam[0]] = $filter->replace($subParam[1], 'friendly-url-param');
} else {
$this->_request['params'][] = $filter->replace($param, 'friendly-url-param');
}
}
拜託糖'filter_var($海峽,FILTER_VALIDATE_EMAIL )'而不是一個正則表達式不匹配一大堆有效的ema il地址,已被[覆蓋]的主題(http://stackoverflow.com/questions/201323)[這裏](http://stackoverflow.com/questions/1903356)[at](http:// stackoverflow。 com/questions/703060)[長度](http://stackoverflow.com/questions/997078) – DaveRandom
被警告:URI中的冒號[在Windows apache中不允許](https://issues.apache.org/bugzilla/show_bug的CGI?ID = 41441)。因此,最好避免PHP應用程序中的URL冒號。 –
其中一個要求不是Windows服務器;) –