2016-08-17 89 views
0

我做一個加法論壇{} PHP列計數不在行匹配值計數1

if ($_SERVER['REQUEST_METHOD'] == "POST" AND isset ($_REQUEST['addfinal'])) { 

    $name_1 = clear_form_text ($_REQUEST['name_1']); 
    $name_2 = clear_form_text ($_REQUEST['name_2']); 
    $car_name = intval ($_REQUEST['id_car_name']); 


    if (empty ($name_1)) $stop .= "Error text!<br>"; 
    if (empty ($name_2)) $stop .= "Error text!<br>"; 

    if ($stop == false) { 

     $db->query ("INSERT INTO car_class (name_1, name_2, id_car_name) VALUES ('$name_1', '$name_2' '$car_name')") or die ($db->error); 
     $infomessage = "<div class=\"attention-box attention-success\"><p class=\"text-muted\">Add success. <a href=\"index.php?module=school_class\">Back</a></p></div>"; 

    } else { 

     $infomessage = "<div class=\"attention-box attention-danger\"><p class=\"text-muted\">" . $stop . " <a href=\"javascript:history.back();\">Врати се назад</a></p></div>"; 

    } 

} else { 

    $result = $db->query("SELECT id, name FROM car_name"); 
     while ($row = $result ->fetch_array()) 
     $arrayrow[] = $row; 

     foreach ($arrayrow as $row) { 
      $select .= "<option value='".$row['id']."'>".$row['name']."</option>"; 

     } 

    $template->set_block ('car_class-add', '', 'car_class'); 
    $template->set ('car_name', $select, 'car_class'); 

} 

的選擇需要從car_name(ID,姓名)讀取值和car_class

它寫入 id

但是,當我點擊提交給我 Column count doesn't match value count at row 1

凡與此代碼的問題?

謝謝你從上面解決

編輯 問題。 現在的腳本工作,但不寫入值id_car_name只寫0 car_class.id_car_na‌​me = car_name.id爲什麼還是這個問題呢?

回答

2

必須經過 '$ NAME_2' 添加逗號:

$db->query ("INSERT INTO car_class 
        (name_1, name_2, id_car_name) 
       VALUES ('$name_1', '$name_2', '$car_name')") 
     or die ($db->error); 
+0

哦,是謝謝你,現在 工作,但不加'id_car_name'只寫0 'car_class.id_car_name = car_name.id' – Martinovska

+0

當你使用var_dump(intval($ _REQUEST ['id_car_name']))。你得到了什麼 ? – Imanez

+0

什麼要放置以輸入正確的值? – Martinovska

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