獲取可用公寓

使用此查詢我會找到所有可用的公寓。所有可用的公寓都沒有預訂ID。獲取可用公寓

我想要的：當有一個預約ID和狀態將被取消我也希望公寓露面，但我不知道如何...

SELECT a.id, a.num_persons, a.rating, a.lat, a.lng, a.street, a.number 
     ,c.title, c.introduction, c.text, c.area, c.long_term_rental, c.beds 
     , c.features ,c.services_and_equipment, c.terms_and_conditions 
     , m.url 
    FROM appartments AS a 
    INNER JOIN appartments_content AS c on c.parent_id = a.id 
    INNER JOIN meta AS m on m.id = c.meta_id 
    LEFT JOIN appartments_bookings AS b 
      ON (b.appartment_id = a.id 
      AND NOT ((? > b.departure) OR (? < b.arrival)))  
     -- this ? = arrival  that ? = departure 
    WHERE b.id IS NULL 
     AND c.language = ? 
     AND a.hidden = ? 
     AND a.publish_on <= ? 
     AND a.city_id = ? 
     AND a.num_persons >= ? 

    ORDER BY a.num_persons ASC, a.publish_on DESC 
    LIMIT ? OFFSET ?'

我加了這一點：

AND b.status != ? OR NOT ((? >= b.departure) OR (? < b.arrival))) WHERE b.order_id IS NULL

但是這不起作用，我得到的結果。

來源

2011-10-18 Frederik Heyninck

也許你應該在你的問題中包含appartments，appartments_content和appartments_bookings的表定義。 – jan

給出了數據結構，我今天在家裏忘了我的水晶地球儀：P –

不知道MySQL的語法，但改變你的WHERE子句到喜歡的東西......

WHERE（b.id爲空或（b.id IS NOT NULL和b.status = '取消'）） AND c.language = etc等

來源

2011-10-18 14:09:02 OTTA

就是這樣，謝謝 –

獲取可用公寓

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