Postgres在php中查詢日期變量

Question

你能幫我解答下面的問題嗎？

PHP代碼：//

$countdate='2017-01-03'; 
$countsql='SELECT rucid,"databaseType","countLoggedOn","prodCount","nprodCount","countType" FROM "ru_countLog" WHERE "countLoggedOn"=$countdate'; 

- >它給語法錯誤

語法錯誤達到或接近 「$」 LINE 1：... untType」 FROM 「ru_countLog」 WHERE 「countLoggedOn」= $ countdate

Answer 1

也許你應該嘗試這樣

$countdate='2017-01-03'; 
$countsql='SELECT rucid,"databaseType","countLoggedOn","prodCount","nprodCount","countType" FROM "ru_countLog" WHERE "countLoggedOn"='.$countdate; 

希望這有助於

Answer 2

從查詢中刪除內部雙引號：

$countsql = "SELECT rucid, databaseType, countLoggedOn, 
      prodCount, nprodCount, countType 
      FROM ru_countLog 
      WHERE countLoggedOn = $countdate"; 

注意這個查詢很容易受到SQL注入。考慮參數化$countdate。隨着http://php.net/manual/en/function.pg-query-params.php，這將成爲

$countsql = 'SELECT rucid, databaseType, countLoggedOn, 
     prodCount, nprodCount, countType 
     FROM ru_countLog 
     WHERE countLoggedOn = $1'; 

$result = pg_query_params($dbconn, $countsql, array($countdate)); 

其中$dbconn是你的數據庫連接或接近 「$」 LINE 1