PHP：剩下幾天，幾小時和幾分鐘到某個日期？

Question

我試圖讓剩下的天，小時和分鐘到使用php的某個日期。

但是我從我的代碼很奇怪的輸出，看起來像這樣：

-16828 days and -11 hours and -21 minutes and -24 seconds 

未來一段時間內存儲在該格式的mysql數據庫：

29/01/2016 7pm 

所以我徑自並做到這一點：

$Draw_time = "29/01/2016 7pm"; 

$date = $Draw_time; 
$timestamp = strtotime($date); 
$new_date = date('Y-m-d a',$timestamp); 

$seconds = strtotime($new_date) - time(); 

$days = floor($seconds/86400); 
$seconds %= 86400; 

$hours = floor($seconds/3600); 
$seconds %= 3600; 

$minutes = floor($seconds/60); 
$seconds %= 60; 


echo "$days days and $hours hours and $minutes minutes and $seconds seconds"; 

但是，當我運行此代碼，我得到上述奇怪的輸出！

據我所知，這可能是由於一些原因，但我能想到的唯一的事實是，我在使用我的格式a？

請問有人能就這個問題提出建議嗎？

Answer 1

只需使用DateTime類等作爲

$Draw_time = "29/01/2016 7pm"; 

$date = DateTime::createFromFormat("d/m/Y ha",$Draw_time); 
$date2 = new DateTime(); 

echo $diff = $date2->diff($date)->format("%a days and %H hours and %i minutes and %s seconds"); 

Answer 2

試試這個

<?php 

    $Draw_time = str_replace('/', '-', "29/01/2016 7pm"); 

    $now = new DateTime(); 

    $futureDate = new DateTime($Draw_time); 

    $interval = $futureDate->diff($now); 
    echo $interval->format("%a days %h hours %i minutes %s seconds"); 
?> 

Answer 3

試試這個。

$draw_time = "2016/01/29 7pm"; 
$date_time = explode(" ", $draw_time);// make separate date and time in array 
$date = strtotime($date_time[0]); // convert your date(2016/01/29) into php time 
$time = strtotime($date_time[1]); // convert your time(7pm) into php time 
$date = $date + $time; // make total time to count 
$new_Date = $date - (time()); // convert into difference from current time 
$day = $new_Date % 86400; 
$hrs = $new_Date % 3600; 
$min = $new_Date % 60; 
echo "Day= ".(date("d",$day)); 
echo " Hours= ".(date("h",$hrs)); 
echo " Minutes= ".(date("i",$min));