如何正確解析json對象？

-1

我試圖解析這個JSON對象，並通過它來遍歷html來製作表格。在審判中，我無法迴應這些價值觀。我如何正確地做到這一點？如何正確解析json對象？

{"1":{"1":"Employer+EID","2":"File+Creation+Date","3":"File+Creation+Time","4":"Payer+EID","5":"Payer+QID","6":"Payer+Bank+Short+Name","7":"Payer+IBAN","8":"Salary+Year+and+Montd","9":"Total+Salaries","10":"Total+records","11":"","12":"","13":"","14":"","15":""},"2":{"1":"12435800","2":"20160714","3":"0318","4":"12435800","5":"","6":"DBQ","7":"QA79DOHB021104613880010010000","8":"201606","9":"183941.22166664","10":"113","11":"","12":"","13":"","14":"","15":""},"3":{"1":"Record+ID","2":"Employee+QID","3":"Employee+Visa+ID","4":"Employee+Name","5":"Employee+Bank+Short+Name","6":"Employee+Account","7":"Salary+Frequency","8":"Number+of+Working+Days","9":"Net+Salary","10":"Basic+Salary","11":"Extra+hours","12":"Extra+Income","13":"Deductions","14":"Payment+Type","15":"Notes/+Comments"},"4":{"1":"1","2":"27835620341","3":"","4":"SHIJAN+THARAKAN+THOMAS","5":"DBQ","6":"2025","7":"M","8":"30","9":"7300","10":"5000","11":"0.00","12":"2500.00000000","13":"200","14":"","15":""}}

我想：

$data = json_decode($_POST['data'],true); 

//echo count($data); 

echo ($data[4][2]);`

其結果是null JSON。我怎樣才能正確地做到這一點？

來源

2016-07-14 Bineesh

後，您使用'json_decode（）'，使用'的print_r（）'上該數組檢查數組數據。它輸出什麼？ – Ben

echo'$ data [4] [2]'對我有用，回聲27835620341，也許'$ post ['data']'未定義？ – briosheje

適用於我：[https://eval.in/605361](https://eval.in/605361） – FirstOne

你的JSON字符串是 -

$str = '{"1":{"1":"Employer+EID","2":"File+Creation+Date","3":"File+Creation+Time","4":"Payer+EID","5":"Payer+QID","6":"Payer+Bank+Short+Name","7":"Payer+IBAN","8":"Salary+Year+and+Montd","9":"Total+Salaries","10":"Total+records","11":"","12":"","13":"","14":"","15":""},"2":{"1":"12435800","2":"20160714","3":"0318","4":"12435800","5":"","6":"DBQ","7":"QA79DOHB021104613880010010000","8":"201606","9":"183941.22166664","10":"113","11":"","12":"","13":"","14":"","15":""},"3":{"1":"Record+ID","2":"Employee+QID","3":"Employee+Visa+ID","4":"Employee+Name","5":"Employee+Bank+Short+Name","6":"Employee+Account","7":"Salary+Frequency","8":"Number+of+Working+Days","9":"Net+Salary","10":"Basic+Salary","11":"Extra+hours","12":"Extra+Income","13":"Deductions","14":"Payment+Type","15":"Notes/+Comments"},"4":{"1":"1","2":"27835620341","3":"","4":"SHIJAN+THARAKAN+THOMAS","5":"DBQ","6":"2025","7":"M","8":"30","9":"7300","10":"5000","11":"0.00","12":"2500.00000000","13":"200","14":"","15":""}}'; 

$result_array = json_decode($str, true); 
echo '<pre>'; print_r($result_array); 
echo $result_array[4][2];

它工作正常的我。請檢查你的變量$_POST['data']。它可能不確定調試這個變量由print_r($_POST);如果這數據指數定義，你會看到諸如數據的索引 -

Array 
(
    ['data'] => 'some_value', 
)

來源

2016-07-14 14:22:44

如何正確解析json對象？

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