Python中找到嵌套元組字符串

Question

我有一個數據庫，我希望能夠搜索，即一個名稱，如果名稱是馬克·克拉姆，它會顯示用戶使用該名稱，我並不需要它所有名字都帶有「Mark」或「Kram」但只有輸入的字符串。我目前的代碼只顯示每個用戶，而不是我搜索的用戶？

（基於評論編輯，刪除多餘的代碼）

find = str(input("Enter the name of the employee you would like to search for: ")) 
    print() 
    for find in record: 
     print("Employee Name: " + find[0]) 
     print("Job title: " + find[1]) 
     #more prints 

Answer 1

您必須查找每個元組中第一項（全名）的匹配。

elif choice == "c": 
    find = str(input("Enter the name of the employee you would like to search for: ")) 
    print() 
    for employee in record: 
     if employee[0] == find: 
      print("Employee Name: " + employee[0]) 
      print("Job title: " + employee[1]) 
      print("Full time: " + employee[2]) 
      print("Hourly Rate: " + employee[3]) 
      print("Years of service: " + str(employee[4])) 
      print() 

您的代碼是一個很好的例子，開始瞭解class es。

Answer 2

取決於有多少條記錄，我會走簡約路線，並通過尋找僱員的姓名記錄迭代：

empName = "Mark Kram" 
for record in records: 
    if record[0] == empName: 
    print "we found the employee!" 
    print record #print the whole employee record 

Answer 3

這是因爲您正在迭代所有記錄並在沒有任何條件的情況下進行打印。您也會立即覆蓋查詢字符串。

elif choice == "c": 
    find = str(input("Enter the name of the employee you would like to search for: ")) 
    print() 
    for employee in record: 
     if employee[0] == find: 
      print("Employee Name: " + employee[0]) 
      print("Job title: " + employee[1]) 
      print("Full time: " + employee[2]) 
      print("Hourly Rate: " + employee[3]) 
      print("Years of service: " + str(employee[4])) 
      print()