我被困在一個非常基本的問題上,我想跳過具有三列重複值的行。在不同列上刪除相同值的行mysql
表飼料
id,type,user_id,friend_id,date
1, 'friend', 4 , 5 , 5/5/2010
2, 'friend', 5 , 4 , 5/5/2010
現在,這是如何將數據保存(我不能改變保存模塊)
因爲兩者具有同樣的事情,所以我想只挑選它們作爲1排不2. 我不想驗證,並在PHP端刪除它,二/三,如果我會在PHP做分頁會擾亂
編輯:
表結構
create table `feed` (
`id` double ,
`type` blob ,
`user_id` double ,
`type_id` double ,
`date` datetime
);
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('78','friends','1314','1313','2012-09-03 19:48:14');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('79','friends','1313','1314','2012-09-03 19:48:14');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('80','friends','1314','1312','2012-09-03 19:49:07');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('82','friends','1313','1312','2012-09-03 19:49:09');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('84','friends','1315','1312','2012-09-03 19:49:24');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('86','friends','1315','1313','2012-09-03 19:49:33');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('87','friends','1313','1315','2012-09-03 19:49:33');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('97','friends','1317','1312','2012-09-03 19:55:06');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('99','friends','1313','1317','2012-09-03 19:56:01');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('100','friends','1317','1313','2012-09-03 19:56:01');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('101','friends','1315','1317','2012-09-03 19:56:58');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('102','friends','1317','1315','2012-09-03 19:56:58');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('104','following','1313','1193','2012-09-03 19:59:39');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('105','following','1313','1308','2012-09-03 19:59:51');
insert into `feed` (`id`, `type`, `user_id`, `type_id`, `date`) values('106','following','1313','1098','2012-09-03 19:59:58');
你想消除同樣的友誼記錄嗎? (如在給定記錄「5是4的朋友」意味着「4是5的朋友」) – mostar
是我想消除同樣的友誼值,B/C 4-> 5和5-> 4是相同的 – MZH
如果答案解決您的問題,請點擊綠色按鈕將其標記爲已接受。 – Zar