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我試圖在搜索後通過API調用顯示多個gif。我能夠讓代碼工作,當我只想顯示一個gif,但我正在尋找迭代JSON文件並顯示多個gif。
我試圖使用$ .each,但每當我做我得到未定義的相關錯誤的組合。我已經嘗試了在JSON數組內調用數據的各種組合,但仍然無法使其工作。
$(document).ready(function(){
$('#gif-search-button').click(function (evt){
evt.preventDefault();
var url ='http://api.giphy.com/v1/gifs/search?api_key=dc6zaTOxFJmzC';
var gifRequest = 'q=' + $('#gif-search').val();
gifCallback = function (data) {
var returnedgif = '<div>';
$.each(data, function(index, gif){
returnedgif += '<a href="' + gif.data.url + '">';
returnedgif += '<img id="resultGif" src="' + gif.data.images.fixed_height.url + '"></a>';
console.log(returnedgif)
})
returnedgif += '</div>'
$('#resultGif').html(returnedgif);
} //End of callback function
$.getJSON(url, gifRequest, gifCallback);
}); //End of click event
});
<div class="container">
<form class='form-group search-form'>
<div class="grid">
<div class="row">
<div class="col-sm-4" >
<label for="gif-search" class='lead'>What type of gif are you looking for?</label>
<input type="text" id="gif-search" class="form-control" placeholder='dancing bears' />
</div>
</div>
<div class="row">
<button type="submit" class='btn btn-danger search-form' id="gif-search-button">Find that gif</button>
</div>
</div>
</form>
<div id="resultGif">
</div>
</div>