如何查詢postgres數組在Ruby on Rails整數使用變量？

Question

Notification.where("uip @> ?", '{1}') 

工作正常，並返回其所有UIP陣列包含1

如果我嘗試但是具有可變以下，我沒有這樣的運氣通知：

ip = 1 

Notification.where("uip @> ?", '{ip}') 

返回錯誤：

Notification Load (1.8ms) SELECT "notifications".* FROM "notifications" WHERE (uip @> '{ip}') 
PG::InvalidTextRepresentation: ERROR: invalid input syntax for integer: "ip" 
LINE 1: ...otifications".* FROM "notifications" WHERE (uip @> '{ip}') 
                   ^
: SELECT "notifications".* FROM "notifications" WHERE (uip @> '{ip}') 
ActiveRecord::StatementInvalid: PG::InvalidTextRepresentation: ERROR: invalid input syntax for integer: "ip" 
LINE 1: ...otifications".* FROM "notifications" WHERE (uip @> '{ip}') 
                   ^
: SELECT "notifications".* FROM "notifications" WHERE (uip @> '{ip}') 

而另一嘗試用：

Notification.where("uip @> ?", ip) 

給出了錯誤：

SELECT "notifications".* FROM "notifications" WHERE (uip @> 1) 
PG::UndefinedFunction: ERROR: operator does not exist: bigint[] @> integer 
LINE 1: ...CT "notifications".* FROM "notifications" WHERE (uip @> 1) 
                   ^
HINT: No operator matches the given name and argument type(s). You might need to add explicit type casts. 
: SELECT "notifications".* FROM "notifications" WHERE (uip @> 1) 
ActiveRecord::StatementInvalid: PG::UndefinedFunction: ERROR: operator does not exist: bigint[] @> integer 
LINE 1: ...CT "notifications".* FROM "notifications" WHERE (uip @> 1) 
                   ^
HINT: No operator matches the given name and argument type(s). You might need to add explicit type casts. 
: SELECT "notifications".* FROM "notifications" WHERE (uip @> 1) 

所以，我怎麼能簡單地找到在軌Postgres的陣列內的整數變量的對象？

謝謝！

Answer 1

有多種方式，你可以在一個Postgres陣列查詢使用ActiveRecord：

固定查詢：

ip = 1  
Notification.where("uip @> '{?}'", ip) 

使用 '任意'：

ip = 1 
Notification.where("uip && ARRAY[?]", ip) 

Answer 2

使用它。我認爲這是有幫助的，你

ip = 1 
Notification.where("uip @> ?", "#{ip.to_s.to_i}") 

OR

Notification.where("uip @>?",ip.to_s.to_i) 

Answer 3

試試這一個。我剛搬到你的括號進入條件：

ip = 1 
Notification.where("uip @> '{?}'", ip) 

Answer 4

您需要從輸入中創建一個數組：

Notification.where("uip @> CAST(ARRAY[?] AS BIGINT[])", ip) 
// or 
Notification.where("uip @> CAST(? AS BIGINT[])", '{' + ip.to_s + '}') 
// or 
Notification.where("uip @> CAST('{' || ? || '}' AS BIGINT[])", ip) 

如果您只想測試一個元素，那麼也可以使用重疊（&&）運算符（它應該更快一些）。或者，你可以使用數組ANY結構：

Notification.where("? = ANY (uip)", ip)