通過javascript對象迭代並輸出基於標準

Question

我有對象的數組某些信息，我想從得到的值：

lastChanceSeats: Object 
     assignedSeats: Array[6] 
     0: Object 
      SeatId: "29A" 
      passengerName: "Mr test1 test1" 
      sectorSequence: 1 
     1: Object 
      SeatId: "22A" 
      passengerName: "Mr test1 test1" 
      sectorSequence: 2 
     2: Object 
      SeatId: "29B" 
      passengerName: "Mrs test2 test2" 
      sectorSequence: 1 
     3: Object 
      SeatId: "22B" 
      passengerName: "Mrs test2 test2" 
      sectorSequence: 2 
     4: Object 
      SeatId: "29C" 
      passengerName: "Master test3 test3" 
      sectorSequence: 1 
     5: Object 
      SeatId: "22C" 
      passengerName: "Master test3 test3" 
      sectorSequence: 2 

我想以下列格式呈現數據：

• 首先{passengerName}
• {sectorSequence：1} + {SeatId}
• {sectorSequence：2} + {SeatId}

...那麼同爲乘客二，三等等。

Answer 1

使用一個簡單的模板和循環儘管每個項目產生的輸出：在對象屬性

var data=[ 
    { 
     "SeatId": "29A", 
     "passengerName": "Mr test1 test1", 
     "sectorSequence": 1 
    }, 
    { 
     "SeatId": "22A", 
     "passengerName": "Mr test1 test1", 
     "sectorSequence": 2 
    }, 
    { 
     "SeatId": "29B", 
     "passengerName": "Mrs test2 test2", 
     "sectorSequence": 1 
    } 
] 


function template(ob, str){ 
    return str.replace(/{([\w\s.\$]+?)}/g, 
    function(j,a){ return ob[a]||""; }); 
} 

strTemplate="First {passengerName} {sectorSequence} + {SeatId}"; 

out=$(data).map(function(i,item){ return template(item, strTemplate)}).toArray().join("\n"); 

alert(out); 

/* result: 
First Mr test1 test1 1 + 29A 
First Mr test1 test1 2 + 22A 
First Mrs test2 test2 1 + 29B */ 

Answer 2

有序的迭代是不可能的。

你可以做這樣的事情：

var data=[ 
    { 
     "SeatId": "29A", 
     "passengerName": "Mr test1 test1", 
     "sectorSequence": 1 
    }, 
    { 
     "SeatId": "22A", 
     "passengerName": "Mr test1 test1", 
     "sectorSequence": 2 
    }, 
    { 
     "SeatId": "29B", 
     "passengerName": "Mrs test2 test2", 
     "sectorSequence": 1 
    } 
], 
orderedObjectProps = ['SeatId', 'passengerName', 'sectorSequence'], 
dataLength = data.length, 
propsLength = orderedObjectProps.length, 
i = 0; 

for(i; i < dataLength; i++) { 
    var obj = data[i], 
    j = 0; 
    for(j; j < propsLength; j++) { 
    var propName = orderedObjectProps[j], 
    propValue = obj[propName]; 
    console.log(propValue); 
    } 
} 

上面的代碼將在你想要的順序打印值。