猛砸這裏文檔<< - 跳過前面的空格

Question

我可以這樣做：

declare foo -r -d '' <<- 'EOF' 
->-> Sopra la panca 
->-> la capra campa 
EOF 

（其中->表示TAB）

然後領先的標籤將被忽略。

可以使用<<-跳過/忽略前導space s，而不僅僅是tab s？

Answer 1

引述 from Greg

 
In this form, all leading tab characters (not spaces!) will be removed. There is 
no provision for removing leading spaces, or leading tabs-and-spaces. (Recall the 
syntactic restrictions of Makefiles, and you'll be OK.)