方法的參數沒有被傳遞到裝飾機

Question

嘿，我有一個方法定義如下：

from x.y import util 
class my_Class(some_object): 
    @util.myDecorator 
    def foo(self, log_file): 
    ''' 
    Test that search entered into the search bar is the search being 
    executed in the job. 
    ''' 
    self.some_page.open() 
    textarea = self.some_page.searchbar 

    searchbar.run_search(log_file.search_string) 
    self.browser.capture_screenshot() 
    self.some_page.jobstatus.wait_for_job_complete() 

    self.verify_equals(
     self.some_page.jobstatus.event_count, 
     log_file.event_count, 
     "Event count doesn't seem to be right.") 

裝飾是在文件util.py

def mydecorator(func): 
    def timeit(*args, **kwargs): 
     start_time = time.time() 
     ret=func(*args, **kwargs) 
     end_time = time.time() 
     print end_time - start_time 
     return ret 
    return timeit 

當我嘗試執行代碼，它在ret=func(*args, **kwargs)失敗，該錯誤消息

TypeError: foo() takes exactly 2 arguments (1 given)

• 我打印* args來的內容（與','.join(str(each) for each in args)），看看它包含的，它打印出來

<....my_Class object at ...>

裝飾工作正常，只有一個ARG（個體經營）方法。我在這裏錯過了什麼嗎？

Answer 1

Whiele你回答意見，要知道，它的工作原理：

>>> import time 
>>> 
>>> def mydecorator(func): 
...  def timeit(*args, **kwargs): 
...   start_time = time.time() 
...   ret=func(*args, **kwargs) 
...   end_time = time.time() 
...   print end_time - start_time 
...   return ret 
...  return timeit 
... 
>>> class my_Class(object): 
...  @mydecorator 
...  def foo(self, arg_1): 
...   print arg_1 
... 
>>> my_Class().foo(100) 
100 
0.0