2017-05-19 47 views
0

在嘗試從數據庫中獲取數據時發生錯誤,該數據基於從前一頁上的i按鈕獲取的id。當我呼應ID只有它給了我正確的ID,但在完整的查詢它給我這個錯誤:帶有消息'SQLSTATE [HY093]的未捕獲異常'PDOException':在從數據庫中獲取信息時

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[HY093]: Invalid parameter number: no parameters were bound' in

我發現了一些關於這個SO答案,但沒有人解決了這個問題,我有。

<?php 
$fetch_article_info = $db->query("select * from news_article where id = :id"); 
    $fetch_article_info->execute(array(':id' => $_GET['id'])); 
$list = $fetch_article_info->fetchAll(PDO::FETCH_ASSOC); 
?> 

下面是一些在db.class我的公開funtions,我認爲可能是有用的

class Database{ 

private $host = DB_HOST; 
private $user = DB_USER; 
private $pass = DB_PASS; 
private $dbname = DB_NAME; 
// database handler 
private $dbh; 
private $error; 

private $stmt; 


public function __construct(){ 
    // Set DSN 
    $dsn = 'mysql:host=' . $this->host . ';dbname=' . $this->dbname; 
    // Set options 
    $options = array(
     PDO::ATTR_PERSISTENT => true, 
     PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION 
    ); 
    // Create a new PDO instanace 
    try { 
     $this->dbh = new PDO($dsn, $this->user, $this->pass, $options); 
    } 
    // Catch any errors 
    catch (PDOException $e) { 
     $this->error = $e->getMessage(); 
    } 
} 
    public function bind($param, $value, $type = null){ 
    if (is_null($type)) { 
    switch (true) { 
     case is_int($value): 
     $type = PDO::PARAM_INT; 
     break; 
     case is_bool($value): 
     $type = PDO::PARAM_BOOL; 
     break; 
     case is_null($value): 
     $type = PDO::PARAM_NULL; 
     break; 
     default: 
     $type = PDO::PARAM_STR; 
    } 
    } 
    $this->stmt->bindValue($param, $value, $type); 
} 
public function query($query){ 
     $this->stmt = $this->dbh->prepare($query); 
    } 

    public function execute(){ 
     return $this->stmt->execute(); 
    } 

    public function resultset(){ 
     $this->execute(); 
     return $this->stmt->fetchAll(PDO::FETCH_ASSOC); 
    } 

    public function single(){ 
     $this->execute(); 
     return $this->stmt->fetch(PDO::FETCH_ASSOC); 
    } 
+0

將'query'變成'prepare'調用,你用佔位符準備一個語句,然後用參數執行它。 '$ fetch_article_info = $ db-> prepare(「select * from news_article where id =:id」);' – Fracsi

+0

@Fracsi感謝您的回覆,在獲得警告之前嘗試過:PDO :: prepare():SQLSTATE [00000]:否錯誤:當我使用準備時未調用PDO構造函數 – marijn

+0

您的錯誤指出問題,您的參數綁定不正確。 – Option

回答

1

您還沒有傳遞到你的執行的功能。見下文。

$db->execute(array(':id' => $_GET['id'])); 
$list = $db->resultset(PDO::FETCH_ASSOC); 

print_r($list); 

// db.php file 
public function execute($params){ 
    return $this->stmt->execute($params); 
} 

public function resultset(){ 
    // $this->execute(); 
    return $this->stmt->fetchAll(PDO::FETCH_ASSOC); 
} 
+0

他正在運行查詢,您不必運行execute。 – Option

+0

在我的本地測試。改變他的代碼後爲我工作。 – devofash

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