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<?php
function saveFile($url, $filename) {
$data = file_get_contents($url);
$fh = fopen($filename, 'w') or die("can't open file");
fwrite($fh, $data);
fclose($fh);
}
$myFile = "images.txt";
$fh = fopen($myFile, 'r');
$theData = fread($fh, filesize($myFile));
$data = explode("\n", $theData);
$count = count($data);
for($i=0;$i<=$count;$i++) {
saveFile($data[$i], basename($data[$i]));
}
?>
這是我的代碼我每次更換打印錯誤PHP下載文件,讀取問題
Warning: fopen(10017226314.jpg) [function.fopen]: failed to open stream: Invalid argument in C:\xampp\htdocs\download\download.php on line 4
can't open file
應該是什麼原因一個動態的文件名?請幫忙。由於
這需要基本調試。你看過'$ filename'嗎?我想你會發現它不包含有效的文件名。 – 2011-04-30 08:58:20