0
我正在使用elasticsearch創建方面。它適用於計數,但我嘗試了更復雜的任務。問題是,我不知道我想要做任務的名稱....elasticsearch聚合(方面與子方面)
我的實際方面查詢:
"facets": {
"name": {"terms": {"field": "name", "size": 20}}
}
響應:
"name": {
"_type": "terms",
"missing": 0,
"total": 11,
"other": 0,
"terms": [
{ "term": "liliales", "count": 4 },
{ "term": "commelinales", "count": 3 },
{ "term": "dioscoreales", "count": 2 },
{ "term": "arecales", "count": 1 },
{ "term": "poales", "count": 1 }
] } }
這是我的數據的一個例子:
name | rank
_________________________________
liliales | accepted
liliales | accepted
liliales | misapplied
liliales | synonym
commelinales | accepted
commelinales | misapplied
commelinales | synonym
dioscoreales | misapplied
dioscoreales | synonym
arecales | accepted
poalesa | synonym
我想爲每個術語,以「等級」像這樣的數子陣列:
"name" : {
"_type" : "terms",
"missing" : 0,
"total" : 11,
"other" : 0,
"terms" : [{
"term" : "liliales",
"count" : 4,
"rank" : {
"accepted" : 2,
"misapplied" : 1,
"synonym" : 1
}
}, {
"term" : "commelinales",
"count" : 3,
"rank" : {
"accepted" : 1,
"misapplied" : 1,
"synonym" : 1
}
}, {
"term" : "dioscoreales",
"count" : 2,
"rank" : {
"misapplied" : 1,
"synonym" : 1
}
}, {
"term" : "arecales",
"count" : 1,
"rank" : {
"accepted" : 1
}
}, {
"term" : "poales",
"count" : 1,
"rank" : {
"synonym" : 1
}
}
]
}
這是什麼kinf方面的的名字,我怎麼能做到這一點嗎?
感謝由提前
非常感謝你。有用 – AlainIb 2014-10-09 15:04:23