字符串中的字符搜索

Question

任何人可以幫助我與我的代碼

int main(void){ 

    int ctr,wordLength; 

    char theWord[99]; 

    ctr = 0; 

    printf("Enter a Word: "); 
    scanf("%s", &); 
    printf("Enter the letter you want to find: "); 
    scanf("%s", &); 

    while(ctr < wordLength | theWord[ctr]=='a'){ 

ctr++; 
    } 

//output 
} 

期待輸出

輸入一個字：你好

輸入你要查找的字母：

在字中未找到字母z。

Answer 1

• 你能做到這樣也

  #include <stdio.h> 
  int main(void) 
  { 
      int ctr; 
      char theWord[99], ch; 
      ctr = 0; 
      printf("Enter a Word: "); 
      scanf("%s", theWord); 
      printf("Enter the letter you want to find: "); 
      scanf(" %c", &ch); 
  
      for(int i = 0; theWord[i]; i++) 
      { 
      if(theWord[i] == ch) 
       ctr++; 
      } 
      if(ctr != 0) 
      printf("word is found\n"); 
      else 
      printf("word is not found\n"); 
  } 
  

• 是的，我們可以做到這一點NG while循環也

  int i = 0; 
  while(theWord[i] != '\0') 
  { 
      if(theWord[i] == ch) 
      ctr++; 
      i++; 
  } 
  if(ctr != 0) 
      printf("word is found\n"); 
  else 
      printf("word is not found\n"); 
  

Answer 2

我做你的代碼的修正，它成功地運作與GCC

#include<stdio.h> 
#include <string.h> 

int main(void){ 

    int ctr = 0,c = 0, wordLength; 

    char ch, theWord[99]; 

    printf("Enter a Word: "); 
    scanf("%s", theWord); 
    printf("Enter the letter you want to find: "); 
    scanf("%c", & ch); 

    wordLength = strlen(theWord); 

    while(theWord[ctr] != '\0') 
    { 
     if (theWord[ctr] == ch) 
     { 
      printf("the letter %c is found in the word\n", ch); 
      c++; 
     } 
     ctr++; 
    } 
     if (c == 0) 
     { 
     printf("the letter %c is NOT found in the word\n", ch); 
     } 
} 

Answer 3

更正代碼

int main (void) 
{ 
    int ctr = 0; 
    int wordLength; 
    char theWord[99], ch; 

    printf("Enter a Word: "); 
    scanf("%s", theWord); 

    printf("Enter the letter you want to find: "); 
    scanf("%c", &ch); 

    while (theWord [ctr] != '\0') 
    { 
     if (theWord [ctr] == ch) 
     { 
      print("Character found at position %1", ctr); 
      break; 
     } 
     ctr++; 
    } 
    if (theWord [ctr] == '\0') 
    { 
     printf ("Character not found"); 
    } 
}