如何使用一個好的按鈕來關閉一個Android彈出窗口

Question

我正在爲一個學校項目製作一個應用程序，並且我卡在一個區域。 我想用一個好的按鈕來解除彈出窗口。 如果您有任何建議或者有更好的方法來實現彈出窗口，請分享它們。

package xyz.ashraf.whoisdelasalle; 

import android.app.Activity; 
import android.os.Bundle; 
import android.util.DisplayMetrics; 

public class Pop extends Activity { 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 

    setContentView(R.layout.popwindow); 

    DisplayMetrics dm = new DisplayMetrics(); 
    getWindowManager().getDefaultDisplay().getMetrics(dm); 

    int width = dm.widthPixels; 
    int height = dm.heightPixels; 

    getWindow().setLayout((int)(width*.8),(int)(height*.5)); 

} 
} 

Java代碼^

<?xml version="1.0" encoding="utf-8"?> 
<ScrollView xmlns:android="http://schemas.android.com/apk/res/android" 
    android:id="@+id/ScrollView01" 
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent"> 
<RelativeLayout 
    android:layout_width="match_parent" android:layout_height="match_parent" 
    android:background="#FAFAFA"> 

<TextView 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:textAppearance="?android:attr/textAppearanceLarge" 
    android:text="John Baptist de La Salle was a French priest, educational reformer, and founder of the Institute of the Brothers of the Christian Schools. He is a saint of the Roman Catholic Church and the patron saint of teachers." 
    android:id="@+id/textView" 
    android:background="#FAFAFA" 
    android:textColor="#000000" 
    android:layout_alignParentTop="true" 
    android:layout_marginTop="15dp" 
    android:layout_marginRight="15dp" 
    android:layout_marginLeft="15dp"/> 

<Button 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:text="OK" 
    android:id="@+id/okButton_who" 
    android:textColor="#00E676" 
    android:background="#FAFAFA" 
    android:layout_below="@+id/textView" 
    android:layout_alignRight="@+id/textView" 
    android:layout_alignEnd="@+id/textView" 
    android:layout_marginTop="50dp"/> 

</RelativeLayout> 
    </ScrollView> 

XML^

提前感謝！

Answer 1

不知道這是否會工作，但你可以嘗試：

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 

    setContentView(R.layout.popwindow); 

    DisplayMetrics dm = new DisplayMetrics(); 
    getWindowManager().getDefaultDisplay().getMetrics(dm); 

    int width = dm.widthPixels; 
    int height = dm.heightPixels; 

    getWindow().setLayout((int)(width*.8),(int)(height*.5)); 

    Button okButton = (Button) findViewById(R.id.okButton_who); 
    okButton.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View v) { 
      finish(); 
     } 
    }); 

} 

或者作爲akadouri建議你可以使用對話框或DialogFragments。

Answer 2

看起來您正在尋找Dialogs或DialogFragments。

Answer 3

我想你可以使用AlertDialog來做到這一點。

AlertDialog.Builder builder = new AlertDialog.Builder(mActivity); 

    builder.setTitle(title);  // If you want a header title 
    builder.setCancelable(false); // If you want to stop user dismissing with back button 
    builder.setMessage(message); // Message to user 

    //If you want custom layout (not needed) 
    LayoutInflater inflater = mActivity.getLayoutInflater(); 
    View dialogView = inflater.inflate(R.layout.pin_dialog, null); 
    builder.setView(dialogView) 

    builder.setPositiveButton(positiveLable, new DialogInterface.OnClickListener() { 
     public void onClick(DialogInterface dialog, int whichButton) { 
      //Do something 
     } 
    }); 

    builder.setNegativeButton(negativeLable, new DialogInterface.OnClickListener() { 
     public void onClick(DialogInterface dialog, int whichButton) { 
      //Do something, or remove if you dont want negative button 
     } 
    }); 

    builder.show();